Help with an algebra factoring problem.

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    Algebra Factoring
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The discussion centers on a user's struggle with an algebra factoring problem involving the expression 15(x-3)^3 + 60x^4(x-3)^2 + 5(x-3). The user is confused about how to proceed after factoring out 5(x-3) and expanding the remaining terms. A key clarification is that (x-3)^2 equals x^2 - 6x + 9, not x^2 - 9, which is crucial for proper distribution. After receiving guidance on distributing and combining like terms, the user expresses relief and clarity regarding the solution process. The conversation highlights the importance of careful distribution and understanding polynomial identities in algebra.
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Sorry to ask help on such an easy problem. I'm self teaching, but for some reason I'm getting stuck on a step. Can anyone explain to me what to do once I reach the form below, prior to the answer?

1) 15(x-3)3 + 60x4(x-3)2 + 5(x-3)




I get this far, as shown below. After this I'm confused as to what to do next. For instance, (x-3)^2, could be x^2-9, allowing me to use difference of squares, but I'm at a loss when I look at the answer my book gives. Somewhere I'm forgetting something. As for 12x^4, I understand that it's been distributed to give the 12x^5-36x^4, but after that I'm completely lost.
3) 5(x-3) [3(x-3)2 + 12x4(x-3) +1]

According to my material the Answer is: 5(x-3)[12x5 - 36x4 +3x2 -18x +28]
 
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just expand the second part and you are okay
 
gohabsgo said:
Sorry to ask help on such an easy problem. I'm self teaching, but for some reason I'm getting stuck on a step. Can anyone explain to me what to do once I reach the form below, prior to the answer?

1) 15(x-3)3 + 60x4(x-3)2 + 5(x-3)




I get this far, as shown below. After this I'm confused as to what to do next. For instance, (x-3)^2, could be x^2-9, allowing me to use difference of squares
No, (x - 3)2 = x2 - 6x + 9, which is different from x2 - 9.
gohabsgo said:
, but I'm at a loss when I look at the answer my book gives. Somewhere I'm forgetting something. As for 12x^4, I understand that it's been distributed to give the 12x^5-36x^4, but after that I'm completely lost.
Factor 5(x - 3) from each of the three terms above, to get what you have just below here. Then expand everything inside the brackets and combine like terms.
gohabsgo said:
3) 5(x-3) [3(x-3)2 + 12x4(x-3) +1]

According to my material the Answer is: 5(x-3)[12x5 - 36x4 +3x2 -18x +28]
 
Mark44 said:
No, (x - 3)2 = x2 - 6x + 9, which is different from x2 - 9.
Factor 5(x - 3) from each of the three terms above, to get what you have just below here. Then expand everything inside the brackets and combine like terms.

Oh wow Mark44, thanks. So all I had to do was distribute 3 through (x2 -6x +9) and combine like-terms? I think where I became confused was with the lone 3. I didn't think to keep x2 -6x +9 in brackets to thereafter distribute 3. It's all so clear now and makes perfect sense. Thanks again for the help on something I was literally going crazy over. :)
 

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