Help with an algebra factoring problem.

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    Algebra Factoring
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Homework Help Overview

The discussion revolves around an algebra factoring problem involving the expression 15(x-3)³ + 60x⁴(x-3)² + 5(x-3). Participants are exploring the steps needed to simplify and factor this expression correctly.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to understand how to proceed after reaching a specific form of the expression. They express confusion regarding the application of the difference of squares and the distribution of terms.
  • Some participants suggest expanding parts of the expression and factoring out common terms, while others clarify misconceptions about the expansion of (x-3)².

Discussion Status

Participants are actively engaging with the problem, offering guidance on how to factor and expand the expression. There is a recognition of the need to distribute and combine like terms, and some participants express clarity after receiving help.

Contextual Notes

There is mention of the original poster being self-taught and feeling stuck, which may indicate a lack of formal instruction on the topic. The discussion also highlights a specific answer provided in their material, which may not align with their understanding.

gohabsgo
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Sorry to ask help on such an easy problem. I'm self teaching, but for some reason I'm getting stuck on a step. Can anyone explain to me what to do once I reach the form below, prior to the answer?

1) 15(x-3)3 + 60x4(x-3)2 + 5(x-3)




I get this far, as shown below. After this I'm confused as to what to do next. For instance, (x-3)^2, could be x^2-9, allowing me to use difference of squares, but I'm at a loss when I look at the answer my book gives. Somewhere I'm forgetting something. As for 12x^4, I understand that it's been distributed to give the 12x^5-36x^4, but after that I'm completely lost.
3) 5(x-3) [3(x-3)2 + 12x4(x-3) +1]

According to my material the Answer is: 5(x-3)[12x5 - 36x4 +3x2 -18x +28]
 
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just expand the second part and you are okay
 
gohabsgo said:
Sorry to ask help on such an easy problem. I'm self teaching, but for some reason I'm getting stuck on a step. Can anyone explain to me what to do once I reach the form below, prior to the answer?

1) 15(x-3)3 + 60x4(x-3)2 + 5(x-3)




I get this far, as shown below. After this I'm confused as to what to do next. For instance, (x-3)^2, could be x^2-9, allowing me to use difference of squares
No, (x - 3)2 = x2 - 6x + 9, which is different from x2 - 9.
gohabsgo said:
, but I'm at a loss when I look at the answer my book gives. Somewhere I'm forgetting something. As for 12x^4, I understand that it's been distributed to give the 12x^5-36x^4, but after that I'm completely lost.
Factor 5(x - 3) from each of the three terms above, to get what you have just below here. Then expand everything inside the brackets and combine like terms.
gohabsgo said:
3) 5(x-3) [3(x-3)2 + 12x4(x-3) +1]

According to my material the Answer is: 5(x-3)[12x5 - 36x4 +3x2 -18x +28]
 
Mark44 said:
No, (x - 3)2 = x2 - 6x + 9, which is different from x2 - 9.
Factor 5(x - 3) from each of the three terms above, to get what you have just below here. Then expand everything inside the brackets and combine like terms.

Oh wow Mark44, thanks. So all I had to do was distribute 3 through (x2 -6x +9) and combine like-terms? I think where I became confused was with the lone 3. I didn't think to keep x2 -6x +9 in brackets to thereafter distribute 3. It's all so clear now and makes perfect sense. Thanks again for the help on something I was literally going crazy over. :)
 

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