Help with an Energy Question please

  • Thread starter Thread starter sopi
  • Start date Start date
  • Tags Tags
    Energy
Click For Summary
SUMMARY

The discussion focuses on calculating variations in potential energy, kinetic energy, total energy, and orbital speed of the Earth as it orbits the Sun. Key formulas provided include the velocity equation v = √[GM_sM_e(2/r - 1/a)] and the total energy equation E = -GM_sM_e/(2a). The semi-major axis for Earth's orbit is specified as a = 149.6 x 10^6 km. The user, Mike, successfully calculated potential energy but seeks assistance with kinetic energy, total energy, and orbital speed calculations.

PREREQUISITES
  • Understanding of gravitational forces and orbital mechanics
  • Familiarity with the concepts of potential and kinetic energy
  • Basic knowledge of mathematical equations involving square roots and fractions
  • Knowledge of the constants GM_s (gravitational parameter for the Sun) and M_e (mass of the Earth)
NEXT STEPS
  • Calculate kinetic energy variations using the provided velocity formula
  • Determine total energy variations based on the semi-major axis
  • Explore the implications of orbital speed changes throughout the year
  • Review the principles of elliptical orbits and their energy characteristics
USEFUL FOR

Students studying astrophysics, educators teaching orbital mechanics, and anyone interested in the energy dynamics of celestial bodies.

sopi
Messages
4
Reaction score
0
Hello. I'm stuck on this question. Any help would be appreciated:

The orbit of the Earth about the Sun is almost circular. The closest and farthest distances are 1.47x10^8 km and 1.52x10^8 km, respectively. Determine the maximum variations in a) potential energy, b) kinetic energy, c) total energy, and d) orbital speed that result from the changing Earth-Sun distance in the course of 1 year.

I got part a) no problem. However, I'm not sure about b), c) or d).

Thanks,
Mike
 
Physics news on Phys.org
You can easily calulate the velocity of the Earth at any arbitrary point on the ellipse:
[tex] v = \left[ GM_sM_e\left(\frac{2}{r}-\frac{1}{a}\right)\right]^{1/2}[/tex]
and the total energy as
[tex] E = -\frac{GM_sM_e}{2a}[/tex]
The semi major axis a for the Earth orbit is [itex]a = 149.6\cdot 10^6km[/itex]
 
Last edited:

Similar threads

  • · Replies 21 ·
Replies
21
Views
8K
  • · Replies 40 ·
2
Replies
40
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
5
Views
3K
Replies
1
Views
2K