# Help with an inclined plane problem

1. Nov 6, 2014

### DudleySquires

Hello folks. After a while lurking I've finally got a problem that I need some help with!

1. The problem statement, all variables and given/known data

I'm designing an adaptor for a drinks optic and have translated one of the aspects of the design into the following problem. There is plenty of stuff on the net about simple inclined plane problems but not quite like this.

In this problem the blue wedge can only move horizontally, constrained by the fixed green floor. The orange pin (viewed here end on) can only move vertically. It doesn't roll and is constrained by the fixed green wall.

The idea of this mechanism (if you haven't already guessed) is that the pin is raised by pushing the wedge under it.

The pin is pressed down by force Fdown.
The wedge is moved horizontally by Fmove.
Ignore gravity.

I need to determine the angle theta in terms of Fdown, μa & μb at the threshold of moving.

As I say, lots of stuff on the net on inclined planes, friction / frictionless, accelerating / equilibrium, but none quite the same as this where the inclined plane is moving under the pin.

2. Relevant equations
At threshold of moving Fmove = Fdown.
ΣFx = ΣFy = 0
μwall-pin = μpin-wedge = μa.
μwedge-floor = μb.

3. The attempt at a solution
I've drawn that many FBDs that it's not worth uploading them all. Suffice to say I know about component forces but I just cant figure how to make everything balance.

2. Nov 6, 2014

### BruceW

hi, I'm glad you're posting interesting problems!
uh, you should probably write down all the important forces, acting on the pin, and acting on the wedge. Then you can start thinking about balancing things afterwards.
So maybe start with the pin. Which frictional forces are acting on it, and which external forces are acting on it? Also remember the normal forces.

3. Nov 6, 2014

### haruspex

Why would that be? Those two forces act at right angles.

4. Nov 7, 2014

### DudleySquires

One of the design constraints is that the force to activate the adaptor Fmove must be <= the force without the adapter Fdown. So I'm trying to deal only with the limit case where they are the same.

5. Nov 7, 2014

### DudleySquires

Here's where I've got to. I've got as far as balancing the pin, then the wedge, and now I'm considering how the friction & perp forces between wall and pin should be accounted for.

I've used a friction coefficient of 0.3, which has resulted in the "slip" beginning at ~17deg. When that happens, the wall begins to react some of the force, which also sets up a new perp and associated friction force between the wall and pin. I suppose that any perp force that cannot be reacted by the friction force will have to be reacted by the ground, which is in addition to the vertical force that is already present.

Last edited: Nov 7, 2014
6. Nov 7, 2014

### DudleySquires

Must admit to being surprised at having created a problem which it appears that nobody has tackled before. As I say I can find nothing on the net. Even if I modify the question to say something like find what value of Fmove is required to move the pin upwards, in terms of theta and the friction coefficients, there is still nothing out there that I can find.

7. Nov 7, 2014

### haruspex

Ok, but then you should have written |Fmove | =|Fdown |, and it should have been as part of the problem description. "Relevant equations" is for standard equations, such as conservation laws.
You need to introduce unknowns for the three normal forces. You do not know in advance what these are. They're not simply components of the force needed to balance gravity. I would suggest not assuming |Fmove | =|Fdown | yet - you can plug that in at the end.
On the roller, you have six forces: gravity, the propulsive force, two normal forces and two frictional forces. Write out two equations containing them.
Likewise the wedge, with its five forces.
Since either nothing moves or sliding occurs at all surfaces, you can take the frictional forces to be at maximum everywhere.
That gives you four equations and four unknowns: the three normal forces and theta. Solve.