- #1

DrManhattanVB

- 21

- 0

## Homework Statement

A 8.80-kg block of ice, released from rest at the top of a 1.03m--long frictionless ramp, slides downhill, reaching a speed of 2.81m/s at the bottom.

need to find the angle between the ramp and horizontal, and what would be the speed of the ice at the bottom if the motion were opposed by a constant friction force of 10.7 parallel to the surface of the ramp?

## Homework Equations

V^2=V0^2+2ay

F=mg or ma

frictional force =mu*F

## The Attempt at a Solution

I tried to find the angle by using the equation :V^2=V0^2+2ay

with it being 2.8^2=(2)(9.8)(1.3)sin(x) with x being the angle, I got 17.9, which didnt work. also i don't see how the mass comes into play in this equation.

Thank you for any help