Help with Calculating 2 mole N2 + H2 = dcm3NH3

[the pro]

Homework Statement

How much dcm³NH₃would we get if 2 mole of N₂ react with the same amount of H₂

Homework Equations

I tried this n=V/V_m then get V=n x V_m then get 2 mole x 22.41 dm₃ x mole ^-1then get 44.82 dcm₃ but i don't now if it is right so any help would be great

The Attempt at a Solution

 

[Yanick]

If by dcm^3 you mean mass (d=m/v --->dv=m?) then you don't need to do all the stuff you wrote down. You need to write down the chemical reaction because the synthesis of ammonia will have a limiting reagent (I'll let you figure that out for yourself). From there you can figure out how many moles of ammonia are made and just use the molar mass to convert to g/Kg of whatever of ammonia.

 

[the pro]

no i was meaning the volume

 

[Yanick]

Well regardless of what you are trying to find you need to start the problem the way I explained above. You will not get 2 mol of ammonia when you mix 2 mol of nitrogen and 2 mole of hydrogen because there will be a limiting reagent.

The volume of the gas will depend on the pressure and temperature of the system and number of mols, the relationship is given by PV=nRT. T is temp in Kelvin, and R is the Rydberg constant (0.08206 L Atm/mol K), P is pressure measured in Atm, V is volume measured in L.