Help with Calculating Net Force, Resistance Forces and Work

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Homework Help Overview

The discussion revolves around a physics problem involving forces, work, and motion. The scenario describes a boy dragging a box at a constant velocity across a level surface, with specific forces and angles provided. Participants are tasked with calculating the net force, resistance forces, and work done against resistance over a given distance.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of Newton's laws, specifically questioning the relationship between net force and acceleration, given the box's constant velocity. There are attempts to clarify the calculations for horizontal force and resistance forces, with some participants expressing uncertainty about connecting velocity to force.

Discussion Status

The discussion is active, with participants exploring different interpretations of the questions. Some have provided guidance on the relationship between net force and resistance forces, noting that the net force is zero due to constant velocity. There is a recognition that the resistive force must balance the applied force, but no consensus on the final answers has been reached.

Contextual Notes

Participants are operating under the constraints of a homework assignment, which may limit the information available for discussion. The original poster expresses difficulty in applying equations and understanding the problem setup.

Jacko_065560
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Hi all, I am having difficulty in understanding this basic phyics relating to force, work,and movement, and I am struggling to do these questions. I would appreciate any help.

The following information was provided and then three questions followed.
A boy drags a box by a rope across a level floor. The box is moving at a constant velocity of 1.6ms-1 west. The boy applies a constant force of 120N along the rope. The rope makes an angle of 30 degrees to the horizontal.
Q1) What is the magnitude of the net force acting on the box?
Q2) Calculate the magnitude of the resistance forces acting on the box. Justify your answer.
Q3) How much work does the boy do against the resistance forces when he drags the box a distance of 5.0m?

I figure that I need to use "F = ma" somewhere, along with the "Work = Fs." I am unsure what else I would use because this is the main problem I am having, applying the equations and rules.

So far, I have managed to do the following workings in an attempt to complete the questions:

1) Using Trig, I calculated that the horizontal line of force acting on box in west direction is equal to 120NCos30 = 103.92N West. Is this the only working I need to do??

2) I think I need to connect the velocity with the 103.92N of horizontal force but I can't think of how to... I have looked through my notes and I guess that Newton's third law can be applied, but I am quite unsure...

3) Well "W = Fs" would be used, with W being unknown, the forces from questions 1 & 2 being substituted for the Net Force F and the displacement, s, would be 5m.

Homework Statement


Homework Equations


The Attempt at a Solution

 
Last edited:
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Unless I've missed something, Q1 ands Q2 seem to be the exact same questions.

Consider the acceleration of the box. Then relate this to the net force, using Newton's second law. (note that the question asks for the magnitude of the net force).

EDIT: Was question 1 supposed to be the force due to the rope?
 


My apologies, I have edited Q2 as above, "Calculate the magnitude of the resistance forces acting on the box. Justify your answer"

RE: EDIT, Question 1 is about the net force, so I take it to be the force in a westerly, horizontal direction and any resistance forces. The rope is at 30 degrees from horizontal so i calculated the horizontal force to be 103.9N (using 120cosine30).

So the acceleration is 0ms-2, because it is moving at a constant velocity of 1.6ms-1
F = ma
Net force = mass x 0...
Net force is 0?
 


the answer to the second question is 0 N because its traveling at a constant speed
 


Jacko_065560 said:
So far, I have managed to do the following workings in an attempt to complete the questions:

1) Using Trig, I calculated that the horizontal line of force acting on box in west direction is equal to 120NCos30 = 103.92N West. Is this the only working I need to do??

Yes, that is all the math you need for this one... But there is no acceleration, therefore no net force. The answer is zero!

Jacko_065560 said:
2) I think I need to connect the velocity with the 103.92N of horizontal force but I can't think of how to... I have looked through my notes and I guess that Newton's third law can be applied, but I am quite unsure...

Again, you know that net force is zero, due to zero acceleration. This means the resistive force exactly balances the force applied through the rope. In order to arrive at zero net force, the resistive force must have the same magnitude, but opposite direction as your calculated force.

Jacko_065560 said:
3) Well "W = Fs" would be used, with W being unknown, the forces from questions 1 & 2 being substituted for the Net Force F and the displacement, s, would be 5m.

Yup!

CH
 


thanks a lot to everyone who helped! i understand now!
 

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