Help with CMOS Circuit Truth Table

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SUMMARY

The discussion focuses on creating a truth table for a CMOS circuit, specifically analyzing the behavior of PMOS and NMOS transistors. The circuit configuration involves a push-pull arrangement where the output inverts the input signal based on the states of the PMOS (P1, P2) and NMOS (N1, N2) transistors. Key insights include the correct biasing of the transistors and the importance of understanding the source-drain impedance of cut-off MOSFETs. The truth table values for the inputs (0,0), (0,1), (1,0), and (1,1) were outlined but require confirmation of the output states.

PREREQUISITES
  • Understanding of CMOS technology and circuit design
  • Familiarity with PMOS and NMOS transistor operation
  • Knowledge of truth tables and logical operations
  • Basic concepts of source-drain impedance in MOSFETs
NEXT STEPS
  • Study the operation principles of PMOS and NMOS transistors in detail
  • Learn how to construct truth tables for various logic circuits
  • Explore the concept of push-pull configurations in CMOS circuits
  • Investigate the effects of source-drain impedance on circuit performance
USEFUL FOR

Electrical engineering students, circuit designers, and anyone interested in understanding CMOS circuit behavior and truth table generation.

majestrooo
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Hope this is the right place for this thread.

Homework Statement



Hi I need help with the truth table for a CMOS circuit.

http://www.isk.kth.se/~william/dd/agda/bild/cmos/mos903.gif

Homework Equations



Truth table and

What type of circuit is this? But I guess that's easy to
answer after setting up the truth table. Right now, I'm not even sure
if the values for P1,p2,n1,n2 are correct.

The Attempt at a Solution



Is this correct?

IN
0 0 -> On: P1,P2, Off: N1,N2 OUT: ?
0 1 -> On: N1,P2, Off: P1, N2 OUT: ?
1 0 -> On: P1,N2, Off: N1,P2 OUT: ?
1 1 -> On: N1,N2, Off: P1,P2 OUT: ?
 
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I believe you're on the right track. Assuming correct biasing, application of a '1' to the gate of a NMOS will turn it on, and pull drain to ground (assuming source is at ground), while application of a '0' to the gate of a PMOS will turn it on, and pull the drain to VDD.

The simplification here is that the output is in a push-pull configuration with PMOS and NMOS gates tied together (so it'll just invert whatever is at their shared gate).

The (slight) complication is that the source terminals of P1 and P2 are not both connected to VDD, nor are their drain terminals both connected to the push-pull CMOSs. But just remember what the source-drain impedance of a cut-off MOSFET is.

Hope this helps, and good luck!
 

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