Help with Complex Acid-Base Titration

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SUMMARY

The discussion focuses on complex acid-base titration involving citric acid as the analyte and a base as the titrant. The participant seeks clarity on the application of the equation C1V1=C2V2, particularly in the context of a 3:1 molar ratio between the base and the acid. It is established that the stoichiometric coefficients must be incorporated into the calculations, leading to a revised equation that reflects the molar relationship. The consensus suggests that relying solely on C1V1=C2V2 can hinder students' understanding of the underlying principles of titration.

PREREQUISITES
  • Understanding of acid-base titration principles
  • Familiarity with stoichiometry and molar ratios
  • Knowledge of citric acid properties and behavior in titrations
  • Basic proficiency in using titration calculations
NEXT STEPS
  • Study the stoichiometric calculations in acid-base reactions
  • Learn about titration curves and their interpretation
  • Explore advanced titration techniques, such as potentiometric titration
  • Review the impact of different acids and bases on titration outcomes
USEFUL FOR

Chemistry students, educators teaching titration methods, and laboratory technicians involved in analytical chemistry will benefit from this discussion.

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Homework Statement
Help! I am confused with my assignment. it was about complex acid base titration. the analyte was citric acid and the titrant was a base. To find it, I need to search for C1V1=C2V2, however during the balanced equation, there is 3 mol of my base that will be reacting to 1 acid. Will the ratio of mol be included in the C1V1=C2V2 equation.? Lets say that C1 is the acid and C2 is the base. What will the equation now? the volume of C2 is missing
Relevant Equations
C1V1=C2V2
Help! I am confused with my assignment. it was about complex acid base titration. the analyte was citric acid and the titrant was a base. To find it, I need to search for C1V1=C2V2, however during the balanced equation, there is 3 mol of my base that will be reacting to 1 acid. Will the ratio of mol be included in the C1V1=C2V2 equation.? Let's say that C1 is the acid and C2 is the base. What will the equation now? the volume of C2 is missing
 
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Forget about C1V1=C2V2, just go for stoichiometry and moles.

Compare with http://www.titrations.info/titration-calculation

The idea of using C1V1=C2V2 to facilitate calculations does IMHO more harm than good to students - they never remember the logic behind, they think the shortcut is the right thing.
 
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