Chemistry Help with Complex Acid-Base Titration

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The discussion centers on the complexities of calculating concentrations in a titration involving citric acid and a base, highlighting confusion over the application of the formula C1V1=C2V2 due to a 3:1 molar ratio. The user questions whether the stoichiometric ratio should be incorporated into the equation, particularly since the volume of the base (C2) is unknown. There is a suggestion to abandon the C1V1=C2V2 formula in favor of a more straightforward approach using stoichiometry and moles for clarity. The conversation emphasizes the potential pitfalls of relying on shortcuts without understanding the underlying principles. Ultimately, a deeper grasp of stoichiometry is recommended for accurate titration calculations.
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Homework Statement
Help! I am confused with my assignment. it was about complex acid base titration. the analyte was citric acid and the titrant was a base. To find it, I need to search for C1V1=C2V2, however during the balanced equation, there is 3 mol of my base that will be reacting to 1 acid. Will the ratio of mol be included in the C1V1=C2V2 equation.? Lets say that C1 is the acid and C2 is the base. What will the equation now? the volume of C2 is missing
Relevant Equations
C1V1=C2V2
Help! I am confused with my assignment. it was about complex acid base titration. the analyte was citric acid and the titrant was a base. To find it, I need to search for C1V1=C2V2, however during the balanced equation, there is 3 mol of my base that will be reacting to 1 acid. Will the ratio of mol be included in the C1V1=C2V2 equation.? Let's say that C1 is the acid and C2 is the base. What will the equation now? the volume of C2 is missing
 
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Forget about C1V1=C2V2, just go for stoichiometry and moles.

Compare with http://www.titrations.info/titration-calculation

The idea of using C1V1=C2V2 to facilitate calculations does IMHO more harm than good to students - they never remember the logic behind, they think the shortcut is the right thing.
 

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