- #1

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1. w + 14 = 1458 to the 4th root.

Thanks for any advice.

EG

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- Thread starter Poker-face
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- #1

- 60

- 0

1. w + 14 = 1458 to the 4th root.

Thanks for any advice.

EG

- #2

Mark44

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I'm not sure what your equation is. Is it this?

1. w + 14 = 1458 to the 4th root.

Thanks for any advice.

EG

[tex]w + 14 = \sqrt[4]{1458}[/tex]

Click on the equation I wrote to see the LaTeX script I wrote for this equation.

If that's the equation you want to solve, there is no factoring needed. All you have to do to solve for w is to add -14 to both sides of the equation.

- #3

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I'm not sure what your equation is. Is it this?

[tex]w + 14 = \sqrt[4]{1458}[/tex]

Click on the equation I wrote to see the LaTeX script I wrote for this equation.

If that's the equation you want to solve, there is no factoring needed. All you have to do to solve for w is to add -14 to both sides of the equation.

Yes. How do you simplfy the square root?

- #4

Mark44

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That's a fourth root.Yes. How do you simplfy the square root?

Simplify it by finding all factors and seeing if any are to the fourth or higher power. For this problem, 1458 = 2 * 729 = 2 * 9 * 81 = 2 * 9

The last expression can also be written as 3

Now use the property of square roots, cube roots, fourth roots, etc. that says

[tex]\sqrt[n]{ab} = \sqrt[n]{a}\sqrt[n]{b}[/tex]

For even roots (square root, fourth root, etc.) in the equation above, both a and b have to be nonnegative. For odd roots (cube root, fifth root, etc.) a and be can be any real numbers.

- #5

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I understand the rule but how you get to step two - 2 x 9 x 81

- #6

Mark44

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729 = 9 * 81. I used the concept I mentioned to you in another thread - if the sum of the digits of a number is 9 or a multiple of 9, the number is divisible by 9.

So 1458 = 2 * 729 = 2 * 9 * 81

- #7

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So 1458 = 2 * 729 = 2 * 9 * 81

Thanks again both threads were a big help!!!

EG

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