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Ok so I tried making myself a free-body diagram but I reached a dead end..

Step 1)f_{kinetic}= μ_{k}n

f_{kinetic}= μ_{k}(251)

f_{kinetic}/ 251 = μ_{k}

Step 2)

F_{x}:

T_{1}

Fn = (m)(g) = 251 N_{y}

120.5 N

Step 3)

ƩF_{x}= m(-a) since it's moving the left or ƩF_{x}= 0 (since it's moving at CONSTANT velocity)

ƩF_{y}= ma

Step 4)

ƩF_{y}: 251 + 120.5 = (25.58 + 12.28)a

*** I got the masses by solving 120.5 = m(9.81) and 251 = m(9.81) ***

ƩF_{y}: 371.5 = (37.86)a

ƩF_{y}: 371.5/37.86 = a

ƩF_{y}: 9.81 = a

Step 5)

T_{1}= m(-a)

T_{1}= (25.58)(-9.81) = 250.9 = 251 :(

Help?

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# Homework Help: Help with finding the coefficient of kinetic friction!

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