- #1

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Ok so I tried making myself a free-body diagram but I reached a dead end..

**Step 1)**f

_{kinetic}= μ

_{k}n

f

_{kinetic}= μ

_{k}(251)

f

_{kinetic}/ 251 = μ

_{k}

**Step 2)**

**F**

_{x}:T

_{1}

**F**

n = (m)(g) = 251 N

_{y}120.5 N

**Step 3)**

ƩF

_{x}= m(-a) since it's moving the left or ƩF

_{x}= 0 (since it's moving at CONSTANT velocity)

ƩF

_{y}= ma

**Step 4)**

ƩF

_{y}: 251 + 120.5 = (25.58 + 12.28)a

*** I got the masses by solving 120.5 = m(9.81) and 251 = m(9.81) ***

ƩF

_{y}: 371.5 = (37.86)a

ƩF

_{y}: 371.5/37.86 = a

ƩF

_{y}: 9.81 = a

**Step 5)**

T

_{1}= m(-a)

T

_{1}= (25.58)(-9.81) = 250.9 = 251 :(

Help?