Help with getting an expression for Electric field from a variable Voltage

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SUMMARY

The discussion focuses on deriving the electric field (E) from a given voltage expression V(x,y,z) = A(x^2, -3y^2, z^2). The user initially misapplies the formula E = V/d by assuming d = (x,y,z), resulting in an incorrect expression for E. The correct approach involves using the Pythagorean theorem to calculate the distance d for equipotential contours, specifically for V = 1280V and y = 2m, leading to the determination of the radius of the equipotential contour.

PREREQUISITES
  • Understanding of electric fields and potentials
  • Familiarity with vector calculus
  • Knowledge of the Pythagorean theorem
  • Basic concepts of equipotential surfaces
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  • Study the derivation of electric fields from voltage expressions
  • Learn about equipotential surfaces and their properties
  • Explore the application of the Pythagorean theorem in three-dimensional space
  • Review the relationship between electric field strength and voltage gradients
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Students preparing for physics exams, particularly those studying electromagnetism, as well as educators seeking to clarify concepts related to electric fields and potentials.

quackzilla
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It gives V(x,y,x) = A(x^2,-3y^2,z^2) and asks for E.


What I have done:

E is equal to V/d , and I assume d = (x,y,x)

Dividing them I get E= A(x,-3y,z)

What am I doing wrong?

I also have another question:

In every plane parallel to the xz-plane the equipotential contours are circles. What is the radius of the equipotential contour corresponding to V=1280V and y=2m? (this is an extension of the previous question).

I have a test tomorrow, and there are a few things I still don't know how to do. Any hints on how to do these would greatly help my studying.
 
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For the second question, you need to use the equation E = V/d. The distance d can be calculated using the Pythagorean theorem: d^2 = (x-2)^2 + z^2. Then you can use this to calculate the radius of the equipotential contour.
 

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