ajk426
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Help with how to do this equation
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Hint: Rationalize the denominator: [math]\dfrac{8 - \sqrt{27}}{2 \sqrt{3}} = \dfrac{8 - \sqrt{27}}{2 \sqrt{3}} \cdot \dfrac{\sqrt{3}}{\sqrt{3}}[/math]
-Dan
-Dan
ajk426
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I've done that but I'm not sure where to go from there.
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You should have gotten a form that looks like [math]a + b \sqrt{3}[/math] so I don't know where the problem is. Please post what you got.ajk426 said:
-Dan
Kansas Boy
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When you multiplied both numerator and denominator by $\sqrt{3}$, what did you get?
Kansas Boy
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Did the problem really say that a and b are real numbers? If so there are infinitely many correct answers. IF the problem had specified "rational number" then there would be a unique answer.