Help with Limits Homework: Evaluate sqrt(tan3x)+sqrt(sin2x)/sqrt(tan2x)

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Homework Help Overview

The problem involves evaluating the limit as x approaches 0 of the expression [sqrt(tan(3x)) + sqrt(sin(2x))] / sqrt(tan(2x)), specifically without using L'Hospital's Rule. This falls under the subject area of calculus, particularly limits and trigonometric functions.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • One participant suggests dividing the limit into two separate limits and considering trigonometric angle sum identities. Another participant expresses difficulty with the square root in their attempts. A third participant reformulates the limit expression to isolate terms under the square roots.

Discussion Status

The discussion is ongoing, with participants exploring different approaches to tackle the limit. Some guidance has been offered regarding the separation of limits and the manipulation of the expression, but no consensus or resolution has been reached yet.

Contextual Notes

The original poster has indicated that this problem is part of an exam review, which may impose certain constraints on the methods used to solve it.

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Homework Statement


evaluate the lim as x->0 of [sqroot(tan3x)+srroot(sin2x)]/sqroot(tan2x) WITHOUT using L'Hospital's Rule
Answer is sqrt3/2 + 1

This is in the exam review for my class, and I am having a hard time getting started on this one. Thanks in advance.


Homework Equations





The Attempt at a Solution

 
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i would divide it into 2 separate limits & try some trig angle sum indentities
 
thanks! ill try it out.
 
Last edited:
ok tried it, but I am having trouble b/c of the sqr root
 
\lim_{x\to 0} \frac{\sqrt{tan3x}+\sqrt{sin2x}}{\sqrt{tan2x}} <br /> = \lim_{x\to 0} \left \sqrt{\frac{tan3x}{tan2x}} +\sqrt{\frac{sin2x}{tan2x}}

so all the operations should be within the sqrt's
 

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