What Are the Characteristics of Oscillations for a Box on a Spring?

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The discussion focuses on the characteristics of oscillations for a box on a spring, with the position described by the equation x = 5.3 m * cos(20/sec * t). The amplitude of the oscillations is identified as 5.3 m, while the angular frequency (ω) is noted as 20 s^-1. The participants are calculating the position of the box at 2 seconds, with initial attempts yielding incorrect results. The calculations involve substituting values into the cosine function, indicating a need for clarification on the correct approach. The conversation emphasizes understanding the relationship between amplitude, angular frequency, and the resulting motion of the box.
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the position of the center of the box shown is given by the equation

x = 5.3 m * cos(20/sec * t)
(a) What is the position of the box 2 seconds after the oscillations have started?

(b) What is the amplitude of the box's oscillations?

(c) What is the period of the box's oscillations?

(d) What is the box's maximum velocity?

(e) What is the box's maximum acceleration?

(f) How long does it take the box to move from -2.65 m to +2.65 m?

for a, i just plugged in 2 for t and got 4.98...but that's wrong not sure where to go from there
Calc:
5.3*cos(20/(1/cos(2)))...sec= 1/cos
 
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Start with x = A cos (ωt). What is A? What is ω?

A = 5.3 m, and ω = 20 s-1
 


so x=5.3*cos(20E-1*2)...5.28?
 
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