Help with point charges and electric fields

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The discussion revolves around calculating the electric field at the center of a square formed by four point charges, two positive and two negative. It is determined that the configuration with like charges at the top and bottom corners yields a greater electric field magnitude than the alternating charge arrangement, which results in cancellation effects. The user struggles with the calculations, initially using the formula E=klql/r^2 but finds it challenging to arrive at the correct answers. The expected results are zero for the first case and -4√2 kq/a^2 for the second case. Assistance is requested to clarify the calculation process.
lyndan
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Homework Statement



So the question states: Four point charges, each of magnitude q, are located at the corners of a square with sides of length a. Two of the charges are +q and two are -q. The charges are arranged in one of the following two ways: (1) The charges alternate in sign (+q,-q,+q,-q) as you go around the square; (2) the top two corners of the square have positive charges (+q,+q) and the bottom two corners of the square have negative charges (-q,-q). (a) In which case will the electric field at the center of the square have the greatest magnitude? explain. (b) calculate the electric field at the center of the square for each of these two cases


The Attempt at a Solution



I already figured out that the electric field will have a greater magnitude in the second case, because the point charges in the first square will essentially cancel each other out? I can't figure out how to calculate the electric field at the center...I started using the E=klql/r^2 but I am just having trouble getting the answer...the first answer is zero and the answer to the second on is -4 2^1/2 kq / a^2 but so far I've been unable to get that

any help would be great thank you so much!
 
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lyndan said:
...the first answer is zero and the answer to the second on is -4 2^1/2 kq / a^2 but so far I've been unable to get that

any help would be great thank you so much!

Hi lyndan! :smile:

Show us how far you've got, and then we'll be able to see where the difficulty is. :wink:
 
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