# Homework Help: Help with simplifying derivatives when sketching graphs

1. May 12, 2010

### TsAmE

1. The problem statement, all variables and given/known data

Sketch the graph of x ^ (4/9) * e ^ (-x)

2. Relevant equations

None.

3. The attempt at a solution

My y' = -x ^ (4/9) * e ^ (-x) ( 1 - 4/9x ^ 1/9). I keep on getting a reaaally long derivative for y'' and thus cannot place it on my sign table. Could someone please show me the correct steps in order to get a simplified y''?

2. May 12, 2010

### Staff: Mentor

You can write y' in two ways - as a sum from the product rule, or as a product. Each form is useful for some purpose.

If y = x4/9e-x,
y' = (4/9)x-5/9 e-x - x4/9 e -x ;; as a sum (actually a difference) straight from the product rule
= e-x x-5/9 (4/9 - x) ;; in factored form

The first form is probably easier to differentiate so that you can get y''. The factored form is more useful if you want to find critical numbers and intervals where y' > 0 or y' < 0.

I think your derivative has an error in it.

3. May 13, 2010

### TsAmE

Oh didnt see that mistake thanks. The only problem I am having is finding y'' since you have to differentiate the sum of 2 products or 3 products which has led me to getting y'' to be almost 2 lines long.

4. May 13, 2010

### Staff: Mentor

If you start with the first form I showed above (the difference, not the factored form), you should be able to write y'' with at most four terms.

5. May 13, 2010

### TsAmE

Oh ok I did as you said now I got a nice simplified

y'' = x^(-14/9) * e^(-x) * ( x^(2) - 8/9x - 20/81 )

but I have no idea how I could factorise the quadratic due to the fractions? Unless I have made some mistake, although I doubt it, cause I checked rigorously

6. May 13, 2010

### Staff: Mentor

Your expression for y'' look fine to me. To factor the quadratic, it's probably most efficient to use the quadratic formula.