# Help with solid of revolution volume question

1. Feb 3, 2014

### student93

1. The problem statement, all variables and given/known data

The problem is attached in this post.

2. Relevant equations

The problem is attached in this post.

3. The attempt at a solution

I used shell's method and set up my integral as 2π∫(4-x)(x^2)dx, from -2 to 2 and got an answer of 128π/3 which is incorrect. The actual answer is 40π/3.

I set my radius as 4-x and I set my height as x^2.

To calculate the limits of integration with respect to x (since I used shell's method), I set x^2=2 and got -2 and 2.

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2. Feb 3, 2014

### jackarms

Your setup is correct, but your limits are not. You have to integrate over the region with respect to x, and stay inside of that region too. Going outside would mean you're creating shells that aren't part of the volume you're calculating. It's usually easiest to find your limits by inspection rather than calculation. In this case, the leftmost side of the region is the origin, and then the rightmost side (as given in the problem) is x = 2. Try those limits instead.

3. Feb 3, 2014

### Dick

You are integrating over a larger region than you should. The part of your region between -2 and 0 isn't really 'enclosed' by your curves.

4. Feb 3, 2014

### student93

Thanks, I ended up getting the correct answer after using the right limits. Also, do you have any suggestions as to how to make sure that I've used the right limits of integration in other similar problems? How do you know when to calculate the limits of integration or when to inspect the graphs for the limits?

5. Feb 3, 2014

### Dick

Make graphs and inspect the graphs for the limits. Always. Don't just blindly solve an equation without looking at what it means for the graphs.