Help with textbook question -- Where did the factor of 2 come from?

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Homework Help Overview

The discussion revolves around a problem from a physics textbook concerning the calculation of magnetic field strength around a current-carrying wire. The original poster questions the use of a factor of 2 in the equation provided in the text, contrasting it with the Biot-Savart Law.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the discrepancy between the textbook's equation and the Biot-Savart Law. Some participants inquire about the evaluation of an integral related to the problem, while others express confusion regarding the application of l'Hôpital's rule in this context.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem, including the integral evaluation and the implications of the factor of 2. There is no explicit consensus yet, but guidance on integral evaluation has been mentioned.

Contextual Notes

Participants note the lack of access to certain computational tools and express a need to review calculus concepts, which may impact their understanding of the problem.

Julia Coggins
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moved into h/w help, so template is missing
From "Physics for Scientists and Engineers" by Randall D. Knight page 1006. A 1 m long, 1.0 mm diameter nichrome heater wire is connected to a 12 V battery. Find the magnetic field strength 1 cm away from the wire. This problem is solved in the book, but they calculate the magnetic field with: μ/2π instead of μ/4π that is in the Biot-Savart Law. Everything else in my calculations was correct, so I'm wondering why they used this? The full equation they used is: B=μ/2π(I/d) related from the Biot Savart Law for a current carrying wire B ={μ/4π}{IΔs×r/r^2} the 'r' in the numerator is the direction of r not the magnitude.
 
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Did you see the preceding example (continued onto the top of page 1006)
where they used Biot-Savart to obtain the equation for B_wire?
 
Reading it now. I don't understand how they evaluated that integral?
 
Julia Coggins said:
I don't understand how they evaluated that integral?
https://www.wolframalpha.com/input/?i=integral(1/sqrt(x^2+d^2)^3,x) (Trig substitution... see step-by-step)
The text gave you the integral to do, then they did the integral (with limits).
Plug in the limits and use l'Hopital's rule... you get "1 - (-1)" = 2
 
Unfortunately I don't have wolfram alpha pro, I do need to brush up on my calc though. Isn't l'hospital's rules dealing with indefinite integrals like this one?
 

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