Highest velocity reached on a hill

In summary: When Alexander sleds down the hill, he experiences a force (F) because of the friction between the ground and the sled. The force is constant, but the velocity (v) is not. The velocity at the bottom of the hill is v^2 - v0^2 = 2as. This means that the highest velocity that Alexander can reach is (v^2-v0^2)/2, or 12.5 m/s.
  • #36
How am I supposed to keep going when I don't understand. Can you explain the equation that is marked with the number 2 ?
 
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  • #37
Drizzy said:
How am I supposed to keep going when I don't understand. Can you explain the equation that is marked with the number 2 ?

First, you wrote:

##F1 = sin(30)mg##

And just stop.

But, sin(30) = 1/2, so ##F1 = mg/2## That's not complicated!

Then you wrote:

F1 - force of friction = ma

And just stop. With 0.85F = force of friction, you have:

mg/2 - 0.85F = ma ...

As I suggested above, I think this problem is too long and complicated. I think you're not used to putting several ideas together. That said, it's not an easy problem and you can see by all those arrows that your teacher got into a bit of tangle trying to solve it!

Maybe someone else can step in, but I think I've shot my bolt on this.
 

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