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Hilbert transform of Sinc
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[QUOTE="roam, post: 5462801, member: 120460"] [h2]Homework Statement [/h2] Show that the Hilbert transform of ##\frac{\sin(at)}{at}## is given by $$\frac{\sin^2(at/2)}{at/2}.$$ [h2]Homework Equations[/h2] The analytic signal of a function is given by ##f_a(t) = 2 \int^\infty_0 F(\nu) \exp(j2 \pi \nu t) \ d\nu,## where ##F(\nu)## is the Fourier transform of the function. We have ##f_a (t) = f(t) +j\hat{f}(t),## where ##\hat{f}(t)## is the Hilbert transform. ##FT(sinc(at)) = \frac{1}{a} \Pi (\frac{\nu}{a})##, where ##\Pi## denotes the rectangular function. [h2]The Attempt at a Solution[/h2] This is the analytic signal whose imaginary part would be the Hilbert transform: $$f_a(t) = 2 \int^\infty_0 FT \Big[ \frac{\sin(at)}{at} \Big] \exp(j2 \pi \nu t) \ d\nu$$ I tried to rewrite this as: $$f_a(t) = 2 \int^\infty_{-\infty} u(t) \ FT \Big[ \frac{\sin(at)}{at} \Big] \exp(j2 \pi \nu t) \ d\nu$$ So, it looks like an inverse Fourier transform, so this becomes ##\left( \frac{1}{j2 \pi \nu} + \frac{\delta(\nu)}{2} \right) \frac{\sin(at)}{at}.## So this is not the correct solution. So here is another approach: $$f_a(t) = 2 \int^\infty_0 FT \Big[ \frac{\sin(at)}{at} \Big] \exp(j2 \pi \nu t) \ d\nu = 2 \int^\infty_0 \frac{1}{|a|} \Pi \left( \frac{\nu}{a} \right) \exp(j2 \pi \nu t) \ d\nu$$ So, how do I continue from here? What method should I use? [/QUOTE]
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Hilbert transform of Sinc
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