Hocky puck vel/displacement/acc

[DarkTangent]

1. By pumping air up through thousands of tiny holes we can make a horizontal air table that will support several pucks so that they can move around on cushions of air with very little friction. Suppose that one such puck initially at rest, having a mass of 0.250 kg, is pushed along by a 1.00 N force for 2.00 s. Determine its acceleration and the final velocity at the end of 2.00 s. What will be the displacement?



2. Well, of all the equations that I thought I should use, I thought it would be Acceleration=(Velocity final-Velocity initial)/(time)



3. I've made several attempts at a solution but I'm not sure if I'm using the right equation, someone mind pushing me in the right path?

 

[DarkTangent]

Never mind. I figured out that f=ma and I know the force and the mass. No biggy :)
The rest will be easy to figure out, thanks :)
Though, it would be (1 kg m/s^2)/ (.250 kg) = 4 m/s^2, correct?

 

[m2003]

I can provide some guidance on how to approach this problem. Let's start with the given information: we have a puck with a mass of 0.250 kg and it is pushed by a force of 1.00 N for 2.00 seconds. We want to determine its acceleration, final velocity, and displacement.

First, we need to understand the concept of acceleration. Acceleration is the rate of change of velocity over time. In other words, it is how quickly the velocity of an object changes over a period of time. The equation you mentioned, a = (vf - vi)/t, is correct. This is known as the average acceleration formula.

To solve this problem, we need to know the initial velocity (vi), final velocity (vf), and time (t). We know that the puck is initially at rest, so the initial velocity is 0 m/s. We also know that the force acting on the puck is 1.00 N for 2.00 seconds. To find the final velocity, we can use the equation vf = vi + at. Plugging in the values, we get vf = 0 + (1.00/0.250)(2.00) = 8.00 m/s. This means that at the end of 2.00 seconds, the puck will be moving at a velocity of 8.00 m/s.

Now, to find the acceleration, we can rearrange the average acceleration formula to solve for a. This gives us a = (vf - vi)/t = (8.00 - 0)/2.00 = 4.00 m/s^2. Therefore, the acceleration of the puck is 4.00 m/s^2.

To find the displacement, we can use the equation d = vit + (1/2)at^2. Again, we know that the initial velocity is 0 m/s, so this term will be eliminated. Plugging in the values, we get d = (1/2)(4.00)(2.00)^2 = 8.00 m. This means that the puck will travel a distance of 8.00 meters in 2.00 seconds.

In conclusion, the acceleration of the puck is 4.00 m/s^2, the final velocity is 8.00 m/s, and the displacement is 8.00 meters. I hope this helps guide you