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symbolipoint

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Keep in mind that set builder notation is of the form

{expression | for <variable(s)> in {a bigger set} such that <condition>}

Here, you're working with integers, so the "bigger set" is going to be Z or Z+ or something.

The tricky part is figuring out a useful condition. For example, if your set was {2, 3, 5, 7, 11}, you could have said: {x | x in Z+ where x is prime and x <= 11}.

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CRGreathouse

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This question is silly. Here are some equally silly answers.

[tex]\{n | n\in\{2, 5, 10, 17\}\}[/tex]

[tex]\{n | (n-2)(n-5)(n-10)(n-17)=0\}[/tex]

[tex]\{n^2+1 | 1\le n\le4\}[/tex]

The polynomial in the second answer can be rewritten as n^4 - 34n^3 + 369n^2 - 1460n + 1700, if you prefer.

[tex]\{n | n\in\{2, 5, 10, 17\}\}[/tex]

[tex]\{n | (n-2)(n-5)(n-10)(n-17)=0\}[/tex]

[tex]\{n^2+1 | 1\le n\le4\}[/tex]

The polynomial in the second answer can be rewritten as n^4 - 34n^3 + 369n^2 - 1460n + 1700, if you prefer.

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symbolipoint

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The first term is obviously just 2.

After that, the next terms conform to 2 plus the sumation as index goes from 2 to i of three plus two times the expression (n-2);

In other words, I'm saying from the second term onward, the term is

2 + summation from 2 to i of (3 + 2(n-2)).

Some variation from that pattern might be possible (not sure) after n=4, since we might not be sure if only four terms as originally given were enough to build the pattern.

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