Homogeneous differential equation

In summary, the problem involves finding the second solution, y2(x), for the differential equation (1-xcotx)y''-xy'+y=0, given that y1(x)=x is a solution and y1 and y2 are linearly independent. The suggested method is to use the substitution y2(x)=u(x)y1(x) and solve for u(x). This results in a more complicated equation, but with careful work, the answer can be obtained.
  • #1
annoymage
362
0

Homework Statement



(1-xcotx)y''-xy'+y=0

y1(x)=x is a solution

find the second solution, y2(x), y1 and y2 are linear independent

Homework Equations



N/A

The Attempt at a Solution



i only know how to find it by auxiliary equation by substitute y=erx
and also i can't use substitution y=xr

how to do this?
 
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  • #2
With these types of problems, where you are given one solution you usually look for a second solution of the form [itex]y_2(x)=u(x)y_1(x)[/itex]. So, try that substitution and see what you get.
 
  • #3
gabbagabbahey said:
With these types of problems, where you are given one solution you usually look for a second solution of the form [itex]y_2(x)=u(x)y_1(x)[/itex]. So, try that substitution and see what you get.

y=ux

y'=u'x+u

y''=u''x+2u

substitute and get

-(x2u''+2xu)cot(x)-x2u'+xu''+2u=0

like this right?

but it seems to become more complicated is it? or should i continue?
 
  • #4
annoymage said:
y''=u''x+2u

You'll want to double check this :wink:
 
  • #5
owho, yes yes, i get the answer. thank you very much.. ^^v
 

What is a homogeneous differential equation?

A homogeneous differential equation is a type of differential equation where all the terms contain the dependent variable and its derivatives. In other words, the equation is homogeneous if it can be written in the form F(x,y,y',y'',...)=0, where F is a homogeneous function. This means that the order of the equation is the same for all terms.

How do you solve a homogeneous differential equation?

To solve a homogeneous differential equation, you can use the substitution method. First, you substitute y=vx into the equation, where v is an unknown function of x. Then, you differentiate both sides of the equation with respect to x, and solve for v. Finally, you substitute back y=vx to get the general solution.

What is meant by the "homogeneous solution" of a differential equation?

The homogeneous solution of a differential equation is the solution obtained by setting the constant of integration to zero. This means that the solution only contains the terms that are homogeneous in the original equation, and does not include any arbitrary constants.

Can a non-homogeneous differential equation be transformed into a homogeneous one?

Yes, a non-homogeneous differential equation can be transformed into a homogeneous one by using the change of variable y=u(x)+v(x), where u(x) is the solution to the corresponding homogeneous equation and v(x) is a particular solution to the non-homogeneous equation. This method is known as the method of variation of parameters.

What are some real-life applications of homogeneous differential equations?

Homogeneous differential equations have many applications in various fields such as physics, engineering, economics, and biology. Some examples include population growth models, chemical reactions, and the motion of a pendulum. They are also used in analyzing the stability of systems and predicting future behavior.

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