Homogenous Differential Equation Solution

[_N3WTON_]

I think that the approach itself is not very different from the variable substitution that you started with (just writing $v = y + x + 1$ rather than $v = y+x$ - you could also see it as making yet another substitution from $v' = v + 1$ to $u = v+1$, which also gives $u' = u$). Regardless, only a very ignorant teacher would deduct points for you using a working method unless explicitly asking for something to be solved with a particular method. But of course this is completely up to you.

thats true...to my knowledge the test doesn't explicitly ask for a certain method so thanks for help :)

 

[ehild]

Thank you...your insight has been very helpful to me :)

You are welcome:)

ehild