Gyroscope
Homework Statement
-kx=m\frac{d^2x}{dt^2}
I don't know how to solve differential equations, can someone show me how to do it, with this example.
The discussion focuses on solving the second-order differential equation derived from Hooke's Law, represented as -kx = m(d²x/dt²). The equation is rewritten as d²x/dt² + (k/m)x = 0, leading to a general solution of the form x(t) = Ccos(ωt) + Dsin(ωt), where ω = √(k/m). The transition from complex exponentials to trigonometric functions is explained using the definitions of cosine and sine in terms of exponentials. The conversation emphasizes the importance of understanding boundary conditions in determining the constants in the general solution.
PREREQUISITESStudents of physics and mathematics, particularly those studying mechanics and differential equations, as well as educators looking for clear explanations of these concepts.
Gyroscope said:Why do you need both solutions?
Gyroscope said:Thanks cristo. How can you pass from e^(something) to cosine and sine functions?
Gyroscope said:Homework Statement
-kx=m\frac{d^2x}{dt^2}
I don't know how to solve differential equations, can someone show me how to do it, with this example.