Horizontal and Vertical Velocity

  • Thread starter kgianqu2
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  • #1
kgianqu2
16
0
A rookie quarterback throws a football with an initial upward velocity component of 16.5 and a horizontal velocity component of 18.3 . Ignore air resistance.

A)How much time is required for the football to reach the highest point of the trajectory?

I got 1.68s which is correct

B) How high is this point?

I can't get the right answer. I got 16.9m by doing: 0m+18.3(1.68)+1/2(-9.8)(1.68)2

Help please!
 

Answers and Replies

  • #2
NasuSama
326
3
A rookie quarterback throws a football with an initial upward velocity component of 16.5 and a horizontal velocity component of 18.3 . Ignore air resistance.

A)How much time is required for the football to reach the highest point of the trajectory?

I got 1.68s which is correct

B) How high is this point?

I can't get the right answer. I got 16.9m by doing: 0m+18.3(1.68)+1/2(-9.8)(1.68)2

Help please!

b) To determine the max height of the projectile, you only need to use the vertical components. You incorrectly used the horizontal component for the displacement formula. It should be...

s = 16.5(1.68) + ½(-9.8)(1.68)²
 
  • #3
kgianqu2
16
0
Thank you!
 

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