Horizontal force by block on a beam

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    Beam Block Force
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The discussion revolves around calculating the forces acting on a hinge due to a block on a beam. Participants clarify that the weight of the beam and the block are critical for determining the tension in the string and the hinge forces. It is emphasized that moving the block affects the torque balance, which in turn alters the tension and horizontal forces at the hinge. The need for a complete problem statement and clear equations is highlighted to facilitate understanding. Ultimately, the conversation underscores the importance of torque in analyzing static equilibrium in this scenario.
  • #31
hello478 said:
i tried to, and they sort of did, but i need someone else to confirm...
thank you for giving me the idea to check my own work you know, never thought of that before
Again with the sarcasm... Seriously...you plug in the value you got into all the equations you used and see if they add to zero. I sure as heck am not giving you any more of my time to a petulant child. Bye.
 
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  • #32
erobz said:
Again with the sarcasm... Seriously...you plug in the value you got into all the equation you used and see if they add to zero. I sure as hell am not giving you any more of my time to a petulant child.
listen please,
im sorry if i did anything wrong, i really didnt mean too, but i didnt like it when you said
"What do you think everyone has been doing?"
i mean, what do you think im trying to do?
i was trying my best to not create a problem for everyone on this little question
and im sorry if you didnt like my sarcasm,
wont do it again!

and yes i tried plugging in the values
and they did add up to 0, but i need someone to confirm it to me

im sorry if you see me as petulant, i was just trying to keep up with you... 👀
once again i sincerely apologise
 
  • #33
hello478 said:
listen please,
im sorry if i did anything wrong, i really didnt mean too, but i didnt like it when you said
"What do you think everyone has been doing?"
i mean, what do you think im trying to do?
i was trying my best to not create a problem for everyone on this little question
and im sorry if you didnt like my sarcasm,
wont do it again!

and yes i tried plugging in the values
and they did add up to 0, but i need someone to confirm it to me

im sorry if you see me as petulant, i was just trying to keep up with you... 👀
once again i sincerely apologise
Apology accepted. All the same, there are plenty of others (I'm one of least qualified) to conceptually explain this to you. Good Luck.
 
  • #34
erobz said:
Apology accepted. All the same, there are plenty of others (I'm one of least qualified) to conceptually explain this to you. Good Luck.
got it!
 
  • #35
hello478 said:
Are my answers correct?

box At A:
T= 6.37
Ty= 4.625
Tx= 3.88
Hx= 3.88
Hy= 16.625
please someone let me know...
 
  • #36
hello478 said:
Are my answers correct?

box At A:
T= 6.37
Ty= 4.625
Tx= 3.88
Hx= 3.88
Hy= 16.625
I think you meant T=6.037N
(Always specify the units.)
 
Last edited:
  • #37
yeah, it was a typo...
i meant 6.037
 
  • #38
hello478 said:
yeah, it was a typo...
i meant 6.037
Ok, so what next? Will you have a go at an answer to the question in post #1, or maybe first try the case of the block being at B?
 
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  • #39
haruspex said:
Ok, so what next? Will you have a go at an answer to the question in post #1, or maybe first try the case of the block being at B?
yeah sure, i will do it in the morning 💤
thank you for the guidance!
 
  • #40
hello478 said:
Are my answers correct?

box At A:
T= 6.37
Ty= 4.625
Tx= 3.88
Hx= 3.88
Hy= 16.625
We prefer you post your calculations, not just the results. But: 80% is correct. Only T is off ( ##T = T_y/\sin\bigl ( {50\over 180}\pi \bigr ) = 6.04## N ) [edit] ah, already noted and a typo

Well done.

:mad: Except you omitted the units -- a strict prof would give you 0 points.
[edit] haha, already noted too

##\ ##
 
  • #41
hello478 said:
and why does tension change when the block is moved
Conceptual intermezzo:

1711667448754.png
This is a (practically massless) swing and you (with substantial mass) sit in the middle.
The tension in the two ropes is equal and each is half your ##mg## (you just hang there and don't swing).
What happens to these tensions when you shift towards the right rope ?
What happens when you move even further, to the other side of the rope ?

Catch my drift ?

(it was rather a long dinner -- again :rolleyes:)

##\ ##
 
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  • #42
BvU said:
What happens to these tensions when you shift towards the right rope ?
What happens when you move even further, to the other side of the rope ?
thank you for the explanation :)
when we shift towards right the tension in the right rope increases
and if we dang towards the left rope the tension in the left rope increase
am i right? or wrong?
 
  • #43
AN ATTEMPT TO THE ORIGINAL QUESTION:::::: is this correct?? 😶‍🌫️
The block is now moved closer to end A of the beam. Assume that the beam remains
horizontal.
State and explain whether this change will increase, decrease or have no effect on the horizontal
component of the force exerted on the beam by the hinge

so the answer to this question would be...
that the resultant tension in the rope decreases
and the horizontal component of the tension also decreases
before horizontal component is 10.9N and as it moves closer to A i decreases and at A it eventually becomes 3.88N
 
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  • #44
AT B:
T= 21.7 N
Tx= 13.95 N
Ty= 16.625 N
Hx= 13.95 N
Hy= 4.625 N (acting downwards)
while at A Hy= 16.625 N acting upwards
 
  • #45
Bingo ! :dademyday:

And with units !

##\ ##
 
  • #46
BvU said:
Bingo ! :dademyday:

And with units !
yesss finally!!:partytime:
 

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