Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Introductory Physics Homework Help
Solving for Building Height and Time in Horizontal Projectile Motion
Reply to thread
Message
[QUOTE="harujina, post: 4524531, member: 487757"] [h2]Homework Statement [/h2] A ball is thrown horizontally from the top of a building and lands 20.0m away from it. If the ball is initially thrown at a velocity of 10.0m/s, how high is the building? How long does it take for the ball to reach the ground? [h2]Homework Equations[/h2] dv = Viv * t + 1/2a * t [h2]The Attempt at a Solution[/h2] dh (horiz.distance) = 20.0m Vh = 10.0m/s Viv (vertical init. velocity) = 0m/s a = -9.8m/s dv (vert. distance) = ? t = ? I'm confused because I'm missing two of the variables which are needed in the equation that will solve this problem...? (dv and t) [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Introductory Physics Homework Help
Solving for Building Height and Time in Horizontal Projectile Motion
Back
Top