Horizontal ring water main pressure drop

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SUMMARY

The discussion focuses on calculating flow rates and pressure drops in a horizontal ring water main system. Water enters the main at 50 psig and is discharged at two points, B and C, with flow rates of 20 gpm and 60 gpm, respectively. The frictional pressure drop is defined by the equation –Δp = 0.0002Q²L, where L is the pipe length in feet and Q is the flow rate in gpm. Participants suggest using the mechanical energy balance and setting up equations to solve for unknowns in the system.

PREREQUISITES
  • Understanding of fluid dynamics principles
  • Familiarity with pressure drop calculations in piping systems
  • Knowledge of the mechanical energy balance
  • Basic proficiency in algebra for solving equations
NEXT STEPS
  • Study the Darcy-Weisbach equation for head loss in pipes
  • Learn about minor losses in piping systems and how to calculate them
  • Explore the concept of flow rate distribution in parallel piping systems
  • Investigate the use of computational fluid dynamics (CFD) software for complex flow scenarios
USEFUL FOR

Engineers, particularly those in civil and mechanical fields, as well as students studying fluid mechanics and hydraulic systems, will benefit from this discussion.

chemengineer23
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Homework Statement


The accompanying figure shows a horizontal ring main consisting of a single loop of pipe, as might be used for supplying water to various points on one floor of a building. Water enters the main at A at 50 psig and is discharged at B and C at rates of 20 gpm and 60 gpm, respectively. Tests on the particular pipe forming the main show that the frictional pressure drop
(psi) is given by –Δp = 0.0002Q2L, where L is the pipe length in feet and Q is the flow rate in gpm. Estimate the flow rates in the individual sections AB, BC and AC, and the pressures at B and C. The distances are AB = 100 ft, BC = 50 ft and AC = 200 ft

7b896101a01606b79ad595086f6349b2.jpg


The Attempt at a Solution


I used the mechanical energy balance.
I'm left with P1/rho=(P2/rho)+hf
hf= Pipeline + Minor Losses
hf= Pipeline + 0
Pipeline= ((4fL)/D)*(Velocity^2)/2
mass flow= 80 gpm
 
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As far as I can oversee this, the place of your ((4fL)/D)*(Velocity^2)/2 is taken by the given –Δp = 0.0002Q2L, right ?

Now try and approach this a bit more systematically: you have some givens, you have some equations (you do, I suppose, even though part 2 from the template has mysteriously disappeared ?) and you have some unknowns. Work towards setting up N equations with N unknowns, then solve them.

And make (also for yourself) a list of symbols you use. P1 ? P2 ?
 

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