Points A and B are separated by 3000 ft of new 6-in schedule-40 steel pipe. 800 gpm of 60 deg F of water flow from point A to point B. Point B is 60 ft above point A. What must be the pressure at Point A if the pressure at B must be 50 psig?
PA/ρg + VA2/2g + ZA = PB/ρg + VB2/2g + ZB + hf
Since, VA = VB and ZA=0, Bernoulli equation can be simplified to:
PA/ρg = PB/ρg + ZB + hf
The Attempt at a Solution
I am stuck at this point if anyone can help I would greatly appreciate it