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Engineering hydraulics question

  • Thread starter mohamadali
  • Start date
  • #1

Homework Statement



Points A and B are separated by 3000 ft of new 6-in schedule-40 steel pipe. 800 gpm of 60 deg F of water flow from point A to point B. Point B is 60 ft above point A. What must be the pressure at Point A if the pressure at B must be 50 psig?


Homework Equations



PA/ρg + VA2/2g + ZA = PB/ρg + VB2/2g + ZB + hf
Since, VA = VB and ZA=0, Bernoulli equation can be simplified to:

PA/ρg = PB/ρg + ZB + hf

The Attempt at a Solution



I am stuck at this point if anyone can help I would greatly appreciate it
 

Answers and Replies

  • #2
rude man
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For Bernoulli you need V, so how would you go about finding V? If you had v you'd be home free, no?

(I assume 6" pipe means 6" diameter. And watch out for p given you as "psig").
 

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