Hot Cold body in contact, what happens with heat and temperature?

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SUMMARY

The discussion centers on the thermal interaction between a hot body and a cold body when they are brought into contact until thermal equilibrium is reached. It is established that the heat lost by the hot body is equal to the heat gained by the cold body, as defined by the principle of energy transfer due to temperature differences. However, the temperature change in each body is not necessarily equal unless their specific heat capacities and masses are identical. The equation ΔT = Q/(mc) illustrates that variations in mass and specific heat capacity affect the temperature changes of the bodies involved.

PREREQUISITES
  • Understanding of thermal equilibrium concepts
  • Familiarity with specific heat capacity
  • Knowledge of heat transfer principles
  • Basic grasp of thermodynamic equations
NEXT STEPS
  • Study the concept of specific heat capacity in detail
  • Learn about the laws of thermodynamics, particularly the first law
  • Explore heat transfer methods, including conduction, convection, and radiation
  • Investigate the mathematical relationships in thermodynamics, focusing on the equation ΔT = Q/(mc)
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Students studying thermodynamics, physics enthusiasts, educators teaching heat transfer concepts, and anyone interested in understanding thermal interactions between bodies.

FelixISF
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Homework Statement


A hot body is brought into contact with a colder body until their temperatures are the same. Assume that no other bodies are around.
1.Is the heat lost by one body equal to the hear gained by the other?
2.Is the temp drop of one body equal to the temp increase of the other?


Homework Equations


No equations needed.


The Attempt at a Solution


I am sure that the heat lost by one is equal to the heat gained by the other, as heat is defined as the energy transferred from one body to the other due to a difference in temp.

But I am not sure if this necessarily implies that the drop in temp of one is equal to the rise in temp of the other?


Could someone please explain?



Thanks!
 
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You are correct for the first part!

For the second part, if I have very large insulated pot of (almost boiling ~100 Celsius) water and put a few ice cubes into it (~0 Celsius), do you think that the equilibrium temperature will be 50 degrees Celsius?

Think about it -- What's an equation that related temperature change to heat energy? Are the two directly equal or are their other variables that you need to consider in that equation?
 
\DeltaT=\frac{Q}{mc}

Okay, this means, that the rise in temp of one will be equal to the drop in temp of the other body, only if their specific heat capacity and mass are the same, right? Otherwise, the drop in temperature might not equal the rise of temperature of the objects.


regards
 
Pretty much. Note that as long as the product, mc, is the same for both, then the temperature drop & increase would be the same.
 

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