How are atomic radii and H-bond strength related?

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Discussion Overview

The discussion revolves around the relationship between atomic radii and hydrogen bond strength, particularly in the context of comparing the boiling points of HF and HCl. Participants explore how electronegativity and atomic size influence intermolecular forces and boiling points.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Casey notes that the boiling point of HF is higher than that of HCl due to fluorine's higher electronegativity, leading to stronger hydrogen bonds.
  • Another participant suggests that the smaller atomic radius of HF compared to HCl contributes to stronger hydrogen bonds, making it harder for molecules to separate.
  • A different participant mentions the dipole moment's relation to electronegativity differences and distance between charges, indicating that a greater dipole moment results in stronger intermolecular attractions.

Areas of Agreement / Disagreement

Participants express various viewpoints on how atomic radii and electronegativity relate to hydrogen bond strength, but no consensus is reached on the exact correlation or implications of these factors.

Contextual Notes

Some participants indicate a lack of explicit coverage of these concepts in their courses, suggesting potential limitations in their understanding of the relationship between atomic radii and hydrogen bonding.

Saladsamurai
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I answered a question that my professor asked: "Why is the boiling point of HF much higher than that of HCl even though HCl has a larger molar mass?"

The answer had to do with F being more electronegative than Cl and thus making stronger H-bonds.

He also said on an aside that it all boils down to atomic radii. What did he mean by that? How are the two correlated?

Thanks!
Casey
 
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Saladsamurai said:
I answered a question that my professor asked: "Why is the boiling point of HF much higher than that of HCl even though HCl has a larger molar mass?"

The answer had to do with F being more electronegative than Cl and thus making stronger H-bonds.

He also said on an aside that it all boils down to atomic radii. What did he mean by that? How are the two correlated?

Thanks!
Casey

A good rule to remember is that H-bonds(such as H-O, H-F, and H-N) > dipole-dipole bonds (such as H-Cl in this case). Another way to look at this is by the atomic radii. The radii for H-F is smaller than H-CL, this makes it much harder to break away due to the Hydrogen being so close to the electronegative Fluorine.

An example for atomic radii, I guess, would be to picture yourself holding someone's hand. Would it be harder to break you two apart while you're closer together or father apart?
 
Saladsamurai said:
I answered a question that my professor asked: "Why is the boiling point of HF much higher than that of HCl even though HCl has a larger molar mass?"

The answer had to do with F being more electronegative than Cl and thus making stronger H-bonds.

He also said on an aside that it all boils down to atomic radii. What did he mean by that? How are the two correlated?

Thanks!
Casey

Study the equation for dipole moment - it is somewhat related to the differences in electronegativity as well as the distance between the charges - the greater the dipole moment within a molecule the greater the intermolecular attraction between molecules.
 
GCT said:
Study the equation for dipole moment - it is somewhat related to the differences in electronegativity as well as the distance between the charges - the greater the dipole moment within a molecule the greater the intermolecular attraction between molecules.

I will look into that. This is a Materials Science course, so we never really covered this stuff explicitly.

I will do some Wiki-ing :smile:
 

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