How Are Cos(x) and Cosh(x) Related in Mathematical Identities?

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SUMMARY

The discussion clarifies the relationship between the cosine function, cos(x), and the hyperbolic cosine function, cosh(x), through their definitions using exponential functions. It establishes that cos(x) is defined as cos(x) = (e^(ix) + e^(-ix)) / 2, while cosh(x) is defined as cosh(x) = (e^(x) + e^(-x)) / 2. The confusion arises when substituting x with ix; this leads to the identity cosh(ix) = cos(x), not cosh(x) = cos(x), which is a common misconception.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with exponential functions and their applications
  • Knowledge of trigonometric and hyperbolic functions
  • Basic grasp of mathematical identities and transformations
NEXT STEPS
  • Study the derivation of trigonometric and hyperbolic identities
  • Learn about the Euler's formula and its implications in complex analysis
  • Explore the applications of hyperbolic functions in real-world scenarios
  • Investigate the graphical representations of cos(x) and cosh(x)
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Students studying mathematics, particularly those focusing on complex analysis, trigonometry, and hyperbolic functions, as well as educators seeking to clarify these concepts.

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Homework Statement





Homework Equations


from the identities found on the internet:

[tex]cos(x)=\frac{(e^{ix}+e^{-ix})}{2}[/tex]

and

[tex]cosh(x)=\frac{(e^{x}+e^{-x})}{2}[/tex]



The Attempt at a Solution



Assuming for the definition of cosh(x), if we take x as being equal to (ix), then surely this shows that cosh(x)=cos(x)? Can someone explain why this is wrong please? because i can't see it
 
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It shows cosh(ix)=cos(x), not cosh(x)=cos(x). There's nothing wrong with that.
 

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