How are even and odd functions defined in n-dimensions?

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Even and odd functions in n-dimensions can be defined based on their behavior under transformations of their variables. A function f(x,y,z) is considered odd if f(-x,-y,-z) equals -f(x,y,z), which implies symmetry about the origin. The discussion highlights that while it's common to refer to functions as even or odd with respect to individual variables, the overall classification can be ambiguous without specifying the transformation. The integral of an odd function over a symmetric region, such as a sphere, will yield zero. Thus, the assumption that the function is odd, leading to a zero integral, is valid if the function meets the oddness criteria across all dimensions.
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How are even and odd functions defined in n-dimensions?

In my homework, we had to integrate f(x,y,z)= (x^2)z + (y^2)z + z^3 over a sphere centered at the origin. My answer came out to be 0 and I made the guess that it might be because f(x,y,z) was an odd function. Now, I don't know if this is true. Does this assumption hold:

f(x) is odd if f(-x) = -f(x)
f(x,y,z) is odd if f(-x,-y,-z) = -f(x,y,z) ?

I'm thinking this might just mean it's odd across a plane.I just handed in my assignment and will have to wait 2 weeks before I know if what I did was right or wrong, so I'm asking here to speed things up!
 
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PeteyCoco said:
How are even and odd functions defined in n-dimensions?

In my homework, we had to integrate f(x,y,z)= (x^2)z + (y^2)z + z^3 over a sphere centered at the origin. My answer came out to be 0 and I made the guess that it might be because f(x,y,z) was an odd function. Now, I don't know if this is true. Does this assumption hold:

f(x) is odd if f(-x) = -f(x)
f(x,y,z) is odd if f(-x,-y,-z) = -f(x,y,z) ?

I'm thinking this might just mean it's odd across a plane.I just handed in my assignment and will have to wait 2 weeks before I know if what I did was right or wrong, so I'm asking here to speed things up!
I'm not sure about whether we refer to functions of more than one variable as even or odd in an overall sense, although I doubt that we do.

However, it's common to refer to a function of more than one variable as being even or odd with respect to an individual variable.

Factor z out of your function: f(x, y, z) = z(x2 + y2 + z2) .
 
PeteyCoco said:
f(x,y,z) is odd if f(-x,-y,-z) = -f(x,y,z) ?
The parity transformation takes (x,y,z) to (-x,-y,-z). It's common to say f has even or odd parity if f(-x,-y,-z) is equal to, respectively, f(x,y,z) or -f(x,y,z). But as SammyS noted, when you have more than one variable, it's ambiguous if all you say is "f is odd." You should specify under what type of transformation is the function odd.
 
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Since the region of integration is symmetric in all three coordinates, the integral will be zero if the function is odd wrt any of the three.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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