How are these two equations the same?

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The discussion clarifies that the two limits, \(\lim_{n\to\infty}\frac{8^{n-1}}{9^{n}}\) and \(\frac{1}{9}\lim_{n\to\infty}(\frac{8}{9})^{n}\), are equivalent. The presence of \(\frac{1}{9}\) in the second limit arises from the factorization of the first limit, demonstrating that both expressions converge to the same value as \(n\) approaches infinity. This equivalence highlights the importance of understanding limit properties in calculus.

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[tex]\lim_{n\to\infty}\frac{8^{n-1}}{9^{n}}[/tex]

and

[tex]\frac{1}{9}\lim_{n\to\infty}(\frac{8}{9})^{n}[/tex]

In particular, why is there a 1/9 beside the limit instead of a 1/8 in the second equation?
 
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These are not equations, FYI, they are limits, and as limits they are the same.
 

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