How can e^(1/z) be written using the definition of e^z?

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SUMMARY

The discussion focuses on expressing e^(1/z) using the definition of e^z, specifically for complex numbers where z = x + yi. Participants clarify that the variables x and y in the definition do not correspond directly to the real and imaginary parts of z but represent arbitrary values. The transformation involves using Euler's formula, leading to the expression e^(1/z) = e^(1/e^(iθ)) = e^(e^i(-θ)), which simplifies to e^(cos(-θ) + i*sin(-θ)). This approach provides a pathway to further manipulate the expression.

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filter54321
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How do you write e^(1/z) in the other form?

z = x+yi

So we should be able to right it using this definition of e^z, no?

e^z = e^x * [cos(y) + i * sin(y)]

I pushed some numbers around the page for a while but I can't get 1/(x+i*y) to split into anything nice. Is there a trick?
 
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...actually, I think I was confusing myself. The x,y in the definition don't have to be matching up with the x,y from the complex number z. The x,y in the definition correspond to the real and imaginary parts of an arbitrary complex z.Would you plug this into the definition?

real:
x/(x^2+y^2)

imaginary:
-y/(x^2+y^2)
 
filter54321 said:
...actually, I think I was confusing myself. The x,y in the definition don't have to be matching up with the x,y from the complex number z. The x,y in the definition correspond to the real and imaginary parts of an arbitrary complex z.


Would you plug this into the definition?

real:
x/(x^2+y^2)

imaginary:
-y/(x^2+y^2)

simple answer no.

z=x+iy

[Re]z = x [Im]z = y

or z= cosq +isinq => eiq

if you look in your textbook you should have all the definitions necessary
 
e^(1/z)
z = x + iy = e^itheta = cos(theta) + isin(theta)

e^(1/z) = e^(1/e^itheta) = e^(e^i(-theta)) = e^(cos(-theta) + isin(-theta)) = ...

can you go from here?
 
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