How Can Friction Have Two Directions in Finding Tension?

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SUMMARY

The discussion centers on the concept of tension in a physics problem involving friction and reaction forces. The participant successfully calculated the first tension as 68.5 N using the equation F=μR, where R is the reaction force. The confusion arises from the presence of two tensions due to friction acting in opposite directions, depending on the motion of the system. The marking scheme clarifies that friction can act upwards or downwards to prevent slipping, depending on whether the object is on the verge of sliding up or down.

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Homework Statement


http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20%289709%29/9709_w11_qp_43.pdf
number 6, find 2 tension

Homework Equations


F=μR

The Attempt at a Solution


Okay, so R(reaction force)=Tcos30 Tsin30=F+20
the first tension is found, 68.5.

However, I am not understanding how there can be two tensions, as a result of frictions of 2 directions?? the marking scheme says the other friction is to prevent downward motion, but the tension isn't even downwards? How can there be 2 Tensions at the same time
 
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thoradicus said:
However, I am not understanding how there can be two tensions, as a result of frictions of 2 directions?? the marking scheme says the other friction is to prevent downward motion, but the tension isn't even downwards?
The friction can act upwards or downwards, depending on how hard the string pulls.

If the ring is on the verge of sliding up, the friction acts down; on the verge of sliding down, the friction acts up. Friction always opposes slipping between surfaces.
 

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