How Can I Convert Mol Fraction to Percentage?

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SUMMARY

The conversion of mol fraction to percentage is straightforward when using the ideal gas law, which states that mol % is equivalent to volume %. For a gas mixture with a mol fraction of 0.02 for CO2, this translates directly to 2% when expressed as a percentage. To calculate weight percentage, the formula involves molecular weights: wt% = (MW_i * mol%_i) / Σ(MW_j * mol%_j). The confusion arose from an incorrect interpretation of a conversion tool that yielded nonsensical results.

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  • Familiarity with the ideal gas law
  • Basic knowledge of molecular weights and their role in calculations
  • Ability to perform mathematical conversions between fractions and percentages
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Chemists, chemical engineers, and students studying gas mixtures and their properties will benefit from this discussion, particularly those needing to convert mol fractions to percentages accurately.

rwooduk
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Hi, please could someone give me some advice on how I would convert the mol fraction to percentage? i.e. I want a gas mixture of Argon and Carbon dioxide with only 0.02 mol fraction of CO2, what would this be as a percent?

I tried using this:

http://www.convert-me.com/en/convert/percent/mole.html

And when I put 0.02 in I get 1.204*10^24 in the percent term, how can this be a percentage?

Thanks for any help with this.
 
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No idea what that site is doing.

But you can use the ideal gas law to discover that mol % = volume %.
If you want weight % you have to bring in the molecular weights:$$ wt\%_i = {MW_i * mol\%_i\over \Sigma_j MW_j * mol\%_j }$$
 
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BvU said:
No idea what that site is doing.

But you can use the ideal gas law to discover that mol % = volume %.
If you want weight % you have to bring in the molecular weights:$$ wt\%_i = {MW_i * mol\%_i\over \Sigma_j MW_j * mol\%_j }$$

That's extremely helpful thankyou! Ahhh yes I see now, but just airing on the side of caution please could you confrim that 0.02 mol frac would be equal to 0.02%
 

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