How can I derive the period of oscillation for a relaxation oscillator?

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SUMMARY

The discussion focuses on deriving the period of oscillation for a relaxation oscillator, specifically in terms of resistances R1, R2, capacitance RC, and supply voltages VCC and VEE. The user applies fundamental equations from electromagnetism, such as V=IR and C=Q/V, to establish a relationship involving current I and its decay over time. The user successfully derives the expression I = I0Exp[-t/RC] but seeks clarification on relating the output voltage V_out to the current. The discussion highlights the importance of understanding voltage dividers in this context.

PREREQUISITES
  • Understanding of relaxation oscillators and their schematics
  • Familiarity with basic electrical engineering concepts such as Ohm's Law (V=IR)
  • Knowledge of capacitors and their behavior in circuits (C=Q/V)
  • Experience with differential equations and their application in circuit analysis
NEXT STEPS
  • Study the voltage divider rule in detail to understand its application in oscillator circuits
  • Learn about the role of capacitors in relaxation oscillators and how they affect oscillation periods
  • Explore the derivation of oscillation periods in other types of oscillators, such as astable multivibrators
  • Investigate simulation tools like LTspice for modeling relaxation oscillators and visualizing their behavior
USEFUL FOR

Electrical engineering students, circuit designers, and hobbyists interested in oscillator design and analysis will benefit from this discussion.

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Homework Statement


I am having a bit of trouble with a homework problem on relaxation oscillators, the schematic is shown below:

https://webspace.utexas.edu/sz233/Relaxation%20Oscillator.png

The original problem states:
derive a relationship for the period of oscillation for a relaxation oscillator in terms of R1, R2, RC, VCC
and VEE.

Homework Equations



So I know from E&M that
V=IR, and C=Q/V.
also, I know that dq/dt = I

The Attempt at a Solution


from this, I deduce, possibly erroneously, that
V_- = IR +\frac{1}{C} \int I(t)dt
so
0 = R \frac{dI}{dt} + \frac{1}{C} * I(t)
then
\frac{dI}{I} = - \frac{1}{RC} dt
it follows that
I = I0Exp[-t/RC]

given that current doesn't change at the + or - poles on the amplifier, then this should be the same current that goes through V+ thus using the voltage divider formula,
V_out = V_+ * \frac{R_2}{R_1 + R_2}
Now, how do I relate the Vout here with the current from above?
 
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Is there a reason for which the latex code doesn't appear? I pulled the notation direct from the sigma reference in the tool box menu
 
thanks a bunch guys
 

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