Period of Oscillation Homework Statement

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Homework Help Overview

The discussion revolves around deriving the period of oscillation for a particle in a symmetric potential, given the amplitude and the potential energy function. The original poster attempts to show that the period is expressed as an integral involving the potential energy difference.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss setting up the integral for the period based on energy conservation principles and Hamilton's equations. There are attempts to separate variables and integrate, with some participants expressing confusion about specific steps and the appearance of constants in the integral.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance on how to approach the integration. Some participants are questioning their understanding of the algebra involved, while others are encouraging further exploration of the integral setup.

Contextual Notes

There is a note that the original poster should follow forum rules by posting their own attempt if they are seeking help, as the thread is a year old and may not have active participants.

Robben
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Homework Statement



Assume that the potential is symmetric with respect to zero and the system has amplitude ##a##, show that the period is given by : ##T=\sqrt{8m}\int^a_0\frac{dx}{\sqrt{V(a)-V(x)}}.##

Homework Equations



##E = \frac12 m(\frac{dx}{dt})^2+V(x)##

The Attempt at a Solution



For a particle, I know that at ##t=0## if we release it from rest at position ##x=a## we then have ##\frac{dx}{dt}=0## at ##t=0## and thus ##E=V(a)##. So when the particle reaches the origin for the first time it has gone through one quarter of a period of the oscillator. Thus, I have to integrate with respect to t from ##0## to ##\frac{T}{4}## and rearrange the equation ##E## for ##\frac{dx}{dt}##. But from here I am not sure how to set it up properly to get ##T=\sqrt{8m}\int^a_0\frac{dx}{\sqrt{V(a)-V(x)}}.##
 
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Hi. Indeed you already have everything to set up your integral:
If you substitute your value of E in Hamilton's equation, can you separate the variables (functions of x on one side, functions of t on the other)?
 
Goddar said:
Hi. Indeed you already have everything to set up your integral:
If you substitute your value of E in Hamilton's equation, can you separate the variables (functions of x on one side, functions of t on the other)?

I have ##V(a) -V(x) = \frac12m(\frac{dx}{dt}2) \implies 2\sqrt{V(a)-V(x)} = m\frac{dx}{dt} \implies \implies \sqrt{\frac{2}{m}}dt = \frac{dx}{\sqrt{V(a)-V(x)}}## but I am confused on how they to get ##T##.
 
What about integrating both sides? You know the limits of the integrals (for t and x) from your first post, so what do you get?
 
When I am integrate I am not sure how they got the ##\sqrt{8m}##.
 
What do you get when you integrate dt from 0 to T/4?
 
Goddar said:
What do you get when you integrate dt from 0 to T/4?

We will get ##T/4## if we integrate dt from 0 to T/4.
 
Ok, then what is (T/4)⋅(2/m)1/2?
This is just algebra...
 
Goddar said:
Ok, then what is (T/4)⋅(2/m)1/2?
This is just algebra...
Oh wow.. how dumb am I. Thank you very much!
 
  • #10
Can you show step by step procedure? I am confused
 
  • #11
juliocezario30 said:
Can you show step by step procedure? I am confused
The thread is a year old. Quite possibly neither participant still uses PF. If you have been given the same homework problem, please follow forum rules by posting your own attempt. A new thread might be best.
 

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