How Can I Evaluate This Line Integral Using Curl and Double Integrals?

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To evaluate the line integral ∫(y + sin x)dx + (z^2 + cos y)dy + x^3dz along the curve r(t) = <sin t, cos t, sin^2 t>, the discussion suggests using the relationship ∫F∙dr = ∫∫curl F∙n ds, where F is defined as <y + sin x, z^2 cos y, x^3>. The curl of F is calculated as -2zi - 3x^2j + k, and the normal vector n to the surface z = 2xy is given as 2xi + 2yj - k. The dot product of curl F and n results in the expression -14x^2y - 1. The boundaries for the double integral are proposed as 0 ≤ x ≤ 1 and 0 ≤ y ≤ 1, and an alternative representation using polar coordinates is also considered.
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Could someone help me with the following? I am asked to evaluate the line integral of ∫(y + sin x)dx + (z^2+cosy)dy +x^3dz where C is the curve r(t) = <sint, cost, sin2t, 0 ≤t≤2π.

Doesn’t this equal to ∫F∙dr where F = <y + sinx, z^2cosy,x^3> and r = <x,y,z>? So wouldn’t ∫F∙dr = ∫∫curlF∙nds where n is the normal vector to the surface z = 2xy (from the parametric equation, z = 2xy).

I got that curl F is -2zi-3x^2j +k, and that n is 2xi + 2yj –k. So if you take the dot product, you would get -4zx – 6x^2y -1, and if you were to want to substitute for z you would get -8x^2y – 6x^2y -1 or -14x^2y -1.

But I’m not sure what the boundaries of integration is other than that x seems to be between 0 and 1, and y seems to be between 0 and 1 as well? So would the double integral be ∫∫-14x^2y-1dxdy where 0≤y≤1 and 0≤x≤1? Many thanks!
 
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Or actually, on further thought, could you represent integral as ∫∫(-14(cosθ)^2(sinθ)-1)rdrdθ where r is between 0 and 1 and θ is between 0 and 2pi?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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