How can i find 0.13r(as in the 3 recurring) as a fraction

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Homework Help Overview

The discussion revolves around converting the repeating decimal 0.13r (where 3 is recurring) into a fraction. Participants explore various methods and approaches to understand the conversion process.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss breaking down the decimal into simpler parts, such as separating 0.1 and 0.03333r. There are attempts to apply known methods for converting repeating decimals to fractions, with some referencing external resources like Wikipedia.

Discussion Status

The conversation includes various attempts to find the correct fraction representation, with some participants expressing confusion and frustration. There is ongoing dialogue about the correct approach to adding fractions and understanding the relationship between repeating decimals and their fractional forms.

Contextual Notes

Some participants express stress over the problem, indicating a lack of clarity on how to proceed. There are mentions of specific fractions being proposed and questioned, but no consensus has been reached on the final answer.

harlatt
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How can I find 0.13r(as in the 3 recurring) as a fraction

Can anyone give me an idea of how I can find 0.13 as a fraction?
:rolleyes:
 
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think of 0.133r as 0.1 + 0.033333r... and then add the fractions together.
 
Hi there harlatt and welcome to PF,

From wikipedia:
Wikipedia said:
A shortcut in converting a repeating decimal to a fraction

If the repeating decimal is between 0.1 and 1, and the repeating block is n digits long occurring right at the decimal point, then the fraction (not necessarily reduced) will be the n-digit block over n digits of 9. For example,

* 0.444444... = 4/9 since the repeating block is 4 (a 1-digit block),
* 0.565656... = 56/99 since the repeating block is 56 (a 2-digit block),
* 0.789789... = 789/999 since the repeating block is 789 (a 3-digit block), etc.

If the repeating decimal is between 0 and 0.1, and the repeating n-digit block is preceded only by k digits of 0 (all of which are to the right of the decimal point), then the fraction (not necessarily reduced) will be the n-digit block over the integer consists of n digits of 9 followed by k digits of 0. For example,

* 0.000444... = 4/9000 since the repeating block is 4 and this block is preceded by 3 zeros,
* 0.005656... = 56/9900 since the repeating block is 56 and it is preceded by 2 zeros,
* 0.0789789... = 789/9990 since the repeating block is 789 and it is preceded by 1 zero.

For any repeating decimal not perscribed above, it can be written as a sum of a terminating decimal and a repeating decimal of one of the two above types. For example,

* 1.23444... = 1.23 + 0.00444... = 123/100 + 4/900 = 1107/900 + 4/900 = 1111/900
* 0.3789789 ... = 0.3 + 0.0789789... = 3/10 + 789/9990 = 2997/9990 + 789/9990 = 3786/9990 = 631/1665

The whole document can be found here: http://en.wikipedia.org/wiki/Recurring_decimal

Hope this helps:smile:
 
:eek: :eek: :eek: :eek: :eek:

Sorry but i rlly don't get none of it lol
 
ohhhhhh i get it! cheers thanks sooo much!
 
wud it be 3/19 or is tht completely rong
 
its not 3/19, but what was your work that got you there, maybe we can point out an error.
 
harlatt said:
wud it be 3/19 or is tht completely rong
Nope, not quite.
 
erm...

to be honest i don't get it now :(

im gettin rlly stressed cos I've been on this question for bout an hour nd have no clue
 
  • #10
so the numbe .1333 can easily be divided into 0.1 and 0.033333
.1 is easy as 1/10
but using hootenannny's post what would 0.03333333333 in fraction form?
 
  • #11
is it 15/90?
 
  • #12
harlatt said:
erm...

to be honest i don't get it now :(

im gettin rlly stressed cos I've been on this question for bout an hour nd have no clue
Okay, so we have the decimal 0.1\dot{3}; this can be split into two decimals thus;

0.1\dot{3} = 0.1 + 0.0\dot{3}

Now, can you write 0.1 and 0.0\dot{3} as fractions?
 
  • #13
harlatt said:
is it 15/90?
No, but very very close.
 
  • #14
is the whole answer 15/90 I've gone thru what the wikipedia thing has?
 
  • #15
erm..... illl try agen one sec
 
  • #16
The answer is not 15/90. Try doing what was suggested above and show your work
Hootenanny said:
Now, can you write 0.1 and 0.0\dot{3} as fractions?
 
  • #17
nope I am still gettin 15/90

i went

0.133333...= 0.1 + 0.033333
=1/10 + 3/90 = 12/90 + 3/90 = 15/90


where am i goin rong?
 
  • #18
No, try thinking of what 0.333... is as a fraction, then work out the relationship between that and 0.0333...
 
  • #19
i don't rlly no
 
  • #20
You're nearly there, you just need to add the fractions 1/10 and 3/90 together properly, 1/10 shouldn't become 12/90.
 
  • #21
:frown: :frown: :frown:

rlly don't get that, got to go bed now,

shud have come on earlier :(
 
  • #22
harlatt said:
i don't rlly no
Are you saying that you don't know what 0.\dot{3} is as a fraction?
 
  • #23
yh but i was plusin the 2 factions i.e 10 goes into 90 9 times so i times tht by the one nd add it to the 3
 
  • #24
0.3 as a fraction = 3/10 aint it?
 
  • #25
comon I've got to go bed :(
 
  • #26
:( gtg sorri ill wait for one more reply but anymore ill get shouted at
 
  • #27
I meant what is 0.33333333... as a fraction, note the dot above the 3 to denote the recurrence.
 
  • #28
Is it 3/9?
 
  • #29
harlatt said:
Is it 3/9?
Yes, which simplifies to 1/3. But you don't want 0.33333, you want 0.0333333; so what is 0.033333 as a fraction?
 
  • #30
is it 1/30?
 

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