How can I find the coefficient of friction for an object on an inclined plane?

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SUMMARY

The coefficient of friction for an object on an inclined plane can be determined using the angle at which the object begins to slide. In this case, the object weighing 361 grams starts sliding at an angle of 20 degrees. The equation mgsin(θ) - Ff(max) = 0 is used to find the static friction force, where θ is the angle of inclination. The correct approach is to use the angle of 20 degrees directly, rather than a value infinitesimally less, to calculate the coefficient of static friction.

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Homework Statement


So I have and inclined plane at 1 degrees, and on top of it, there is an object 361grams. I gradually increase the angle of the inclined plane, and just at 20 degrees, the object starts to slide down. How do I find out the coefficient of friction?



Any help would be appreciated.

Thanks



Homework Equations





The Attempt at a Solution



I only know that just before it is about to slide down, mgsin20-Ffmax=0
so do i use 19.99999 degrees to solve this equation? So i used mgsin19.999=Usmgcos19.9999

and got 1.299999N but I think its wrong.
 
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Not necessarily when resultant force is 0, the object does not move.

For example, take the case when you are pushing an object with a force [itex]F[/itex], and there is a friction [itex]f[/itex] equal to the force you are applying, the object moves with constant speed [itex]v[/itex], but there is no acceleration. [itex]a = 0[/itex].

[itex]F[/itex]resultant[itex]= m*a[/itex], so when [itex]F[/itex]resultant[itex]= 0[/itex] then you don't have acceleration.

So basically, you don't have to make it 19.9999999, it is 20 degrees.

I have attached a jpeg with the sketched problem. Have a look at it. Good luck
 
Last edited:

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