How can I find the Laplace transform of erf without using tables?

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Homework Help Overview

The discussion revolves around finding the Laplace transform of the error function, specifically f(t) = erf(t^(1/2)), without utilizing tables or computational tools. Participants are exploring various methods to approach this problem.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss performing direct integrations and consider switching the order of integrations. There are suggestions to integrate by parts and to explore multiple methods for the transformation.

Discussion Status

The discussion is active with participants sharing different approaches and methods. Some guidance has been provided regarding integration techniques, but there is no explicit consensus on the best method yet.

Contextual Notes

Participants express frustration with the complexity of the error function and the challenge of avoiding tables or computational aids. There is an emphasis on understanding the integration process involved in the Laplace transform.

janrain
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how do i find the laplace transform of the following error function without using tables?
f(t)=erf(t^(1/2))
i've been trying really long but i seem to be stuck in a loop of erf
 
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janrain said:
how do i find the laplace transform of the following error function without using tables?
f(t)=erf(t^(1/2))
i've been trying really long but i seem to be stuck in a loop of erf

Hey Jarain. Suppose you mean other than Mathematica right?

Just perform the integrations directly then:

[tex]\mathcal{L}\left\{\text{Erf}[\sqrt{t}]\right\}=<br /> \int_0^{\infty}e^{-st}\left[\frac{2}{\sqrt{\pi}}\int_0^{\sqrt{t}} e^{-u^2}du\right]dt[/tex]

Now, can you switch the order of integrations to effect the solution?
 
Last edited:
janrain said:
how do i find the laplace transform of the following error function without using tables?
f(t)=erf(t^(1/2))
i've been trying really long but i seem to be stuck in a loop of erf

Try integrating by parts.
 
Tide said:
Try integrating by parts.

Nice! Thanks.:smile:

Well, then do it both ways Jarain. :rolleyes:

Edit: Oh yea. Tide's way is better.:smile:
 
Hi! I actually just performed this transform recently.
Let dv/dt = [tex]\int e^{-st}[/tex]
Let u = [tex]\int_0^{\sqrt{t}} e^{-x^2} dx[/tex]
 

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