How can I find the length of segment AB using the given line and planes?

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Homework Help Overview

The problem involves determining the length of segment AB formed by the intersection of a given line with the xz- and yz-coordinate planes. The line is defined parametrically, and the intersections are to be found based on the properties of the coordinate planes.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the parametric equations of the line and how to apply them to find intersection points with the coordinate planes. There is a focus on understanding the significance of the normals to the planes and the implications of the coordinates at the intersection points.

Discussion Status

Participants are actively exploring the relationships between the line's equations and the properties of the coordinate planes. Some guidance has been offered regarding the characteristics of points A and B, but there is no explicit consensus on the next steps or methods to be used.

Contextual Notes

There is an emphasis on the specific conditions that define points A and B, such as the y-coordinate being zero for point A and the x-coordinate being zero for point B. The discussion reflects an ongoing exploration of these constraints.

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1. The problem statement:

The line r=(-8,-6,-1) + s(2,2,1) intersects the xz- and yz-coordinates planes at points A and B, respectively. Determine the length of line segment AB.


Homework Equations





The Attempt at a Solution



I know that for the line, x= -8 + 2s, y= -6 + 2s, and z= -1 + s. I think the normals to the xz- and yz- planes are (0,1,0) and (1,0,0) respectively. Do I just stick the parametric equations of the line into the Cartesian equation of each of the planes to get something or do I have to use different numbers?
 
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adrimare said:
1. The problem statement:

The line r=(-8,-6,-1) + s(2,2,1) intersects the xz- and yz-coordinates planes at points A and B, respectively. Determine the length of line segment AB.


Homework Equations





The Attempt at a Solution



I know that for the line, x= -8 + 2s, y= -6 + 2s, and z= -1 + s. I think the normals to the xz- and yz- planes are (0,1,0) and (1,0,0) respectively. Do I just stick the parametric equations of the line into the Cartesian equation of each of the planes to get something or do I have to use different numbers?


Knowing the normals to the two coordinate planes isn't useful in this problem, but something that is useful is that every point on the x-z plane has a y coordinate of 0. There is a similar property for every point on the y-z plane. Can you use this information in your problem?
 
How?
 
You know that the line intersections points A and B, and that these points are on, respectively, the x-z and y-z coordinate planes. What do you know about point A? Point B?
 
That A has a y-value of 0 and B has an x-value of 0. Now what?
 
Use your equation of the line. The two points have to be on the line, right? x= -8 + 2s, y= -6 + 2s, and z= -1 + s.
 

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