How Can I Find the Power Series Representation of the Given Integral Function?

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SUMMARY

The discussion focuses on finding the power series representation of the integral function \( f(x) = \int_{0}^{x} \frac{e^{t}}{1+t} dt \). The user initially employed the Maclaurin series method but seeks a more straightforward approach using the power series of elementary functions. Key series expansions mentioned include \( e^{x} = \sum_{n=0}^{\infty} \frac{x^{n}}{n!} \) and \( \frac{1}{1+t} = \sum_{n=0}^{\infty} (-1)^{n} t^{n} \). The user is looking for guidance on effectively combining these series to derive the desired representation.

PREREQUISITES
  • Understanding of Maclaurin series
  • Familiarity with power series expansions of exponential functions
  • Knowledge of series representation for rational functions
  • Basic calculus concepts, particularly integration
NEXT STEPS
  • Learn how to derive power series from integrals
  • Study the manipulation of series, specifically Cauchy products
  • Explore the convergence of power series and their radius of convergence
  • Investigate advanced techniques in series representation, such as term-by-term integration
USEFUL FOR

Mathematicians, students studying calculus, and anyone interested in series expansions and integral functions.

girolamo
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Hi, I'm trying to find the series representation of [tex]f(x)=\int_{0}^{x} \frac{e^{t}}{1+t}dt[/tex]. I have found it ussing the Maclaurin series, differenciating multiple times and finding a pattern. But I think it must be an eassier way, using the power series of elementary functions. I know that [tex]e^{x}=\sum_{0}^{\infty}\frac{x^{n}}{n!}[/tex] and [tex]\frac{1}{1+x}=\sum_{}^{\infty}(-1)^{n}x^{n}[/tex] but I don't know how to use it here. Thanks

(Don't hesitate to correct my english)
 
Physics news on Phys.org
If ##f(x) = \sum_{n=0}^\infty a_n x^n## then
##\frac{f}{1-x} = \sum_{n=0}^\infty \sum_{j=0}^n a_j x^n##.
 

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