How can I find the velocity of a proton?

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To find the velocity of a proton moving between two charged plates, one must consider the conservation of energy, accounting for both electrical and kinetic energy. The proton is identified based on its charge and behavior, as it slows down while moving from a negatively charged plate at -70V to a less negative plate at -50V. The electric field can be calculated using the potential difference and the distance between the plates, which will help determine the force acting on the proton. Using the force and the mass of the proton, acceleration can be calculated, allowing for the application of kinematic equations to find the final speed. Understanding these principles will lead to the correct solution for the proton's speed as it reaches the right plate.
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Homework Statement



A charged particle (either an electron or a proton) is moving rightward between two parallel charged plates separated by distance d = 2.20 mm. The charge on the left has a potential of -70V and the charge on the right has a potential of -50V. The particle is slowing from an initial speed of 91.0 km/s at the left plate.
(a) Is the particle an electron or a proton?
(b) What is its speed just as it reaches the plate at the right?

Homework Equations



?

The Attempt at a Solution



I understand that the particle is a proton, but I have not the slightest clue as to what equation to use. Any ideas?
 
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peaceinmideas said:

The Attempt at a Solution



I understand that the particle is a proton, but I have not the slightest clue as to what equation to use. Any ideas?

conservation of energy. (both electrical an kinetic).

you can also calculate the size of th electric field, and then the force on the proton, and make it into a standard projectile motion problem.
 
As you travel to the right, the potential _____(increases or decreases?)

Therefore, the plate on the right is _____(positive or negative?) relative to the plate on the left.

Also, since the particle is slowing down, the plate on the right is ____(attracting or repelling?) the charge -- so the charge must be ____(positive or negative?).

Hope that helps.
 
Still have no idea, i was thinking about using Vfinal^2= Vinitial^2 + 2a(Xfinal - Xinitial
) but i am not sure how to find a.
 
peaceinmideas said:
Still have no idea, i was thinking about using Vfinal^2= Vinitial^2 + 2a(Xfinal - Xinitial
) but i am not sure how to find a.

You know how to compute the electric field in a capacitor? You also know the charge of a proton
so you can find out what the force on it is, and you know the mass of a proton, so you can find out a with F=ma
 
peaceinmideas said:
The charge on the left has a potential of -70V and the charge on the right has a potential of -50V.

Does the figure show how far apart those charges are? If you know the distance between them, you can use the two potential values to find the electric field.

The electric field can then be used to find the force on the charge.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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