How Can I Integrate 1/(sin(x)+a) dx?

  • Thread starter Thread starter msbell1
  • Start date Start date
  • Tags Tags
    Dx Integrate
Click For Summary
SUMMARY

The integral ∫dx/(sin(x)+a) can be approached by multiplying the numerator and denominator by (sin(x)-a), resulting in ∫(sin(x)-a)/(sin²(x)-a²) dx. The first term, ∫sin(x)/(sin²(x)-a²) dx, can be integrated using the substitution 1-cos²(x) and partial fractions. The second term, -∫a/(sin²(x)-a²) dx, presents challenges as it leads back to a similar form. A recommended substitution is to rewrite the integrand in terms of tan(x/2) using the substitution tan(x/2)=t, which simplifies the integration process.

PREREQUISITES
  • Understanding of integral calculus and techniques for integration.
  • Familiarity with trigonometric identities and substitutions.
  • Knowledge of partial fraction decomposition.
  • Experience with the substitution method, particularly with tan(x/2).
NEXT STEPS
  • Study the method of integration using trigonometric substitutions, specifically tan(x/2).
  • Research partial fraction decomposition techniques for rational functions.
  • Practice integrating functions involving sin(x) and cos(x) using various substitutions.
  • Explore advanced integration techniques, including the use of complex numbers in integrals.
USEFUL FOR

Students and educators in calculus, particularly those focusing on integration techniques, as well as mathematicians seeking to deepen their understanding of trigonometric integrals.

msbell1
Messages
25
Reaction score
0

Homework Statement


Integrate ∫dx/(sin(x)+a), where a is a constant.

Homework Equations


The Attempt at a Solution


I have been working on this for a while, and for some reason I can't figure it out. The attempt that seemed the most promising to me was to multiply top and bottom by (sin(x)-a), which gave
∫(sin(x)-a)/(sin2(x)-a2) dx.
I could integrate the first term (∫sin(x)/(sin2(x)-a2)dx) by substituting 1-cos2(x) for sin2x, and then using partial fractions. However, the second term (-∫a/(sin2(x)-a2)dx) is causing me some trouble. Actually, with the second term, I again used partial fractions, but then I end up with (sin(x) +/- a) in the denominator, which ends up looking about the same as what I started with. Is there a substitution that would make this problem simple? Thanks.
 
Physics news on Phys.org
The integrand is a rational function of sin(x): rewrite it in terms of tan(x/2) and use the substitution tan(x/2)=t.
(sin(x)=2tan(x/2)/(1+tan2(x/2), cos(x)=(1-tan2(x/2)/(1+tan2(x/2). )

ehild
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 44 ·
2
Replies
44
Views
6K
Replies
9
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 22 ·
Replies
22
Views
3K