I have to solve the following integral
1/(sqrt[x] * ln[x]) from 2 to infinity
The Attempt at a Solution
u= ln[x] dv=1/sqrt(x)
du= 1/x v= 2 sqrt(x)
If I do this I get
lim (ln b/ sqrt[x] - 4 sqrt[x] - ln2/sqrt[x] + 4 sqrt[x])
Is this the actual result of the integral? Did I substitute correctly?
Thanks in advance!